According to Boyle’s law, PV= K, what was the volume at the time of the first measurement given the following information? Round

Question

Len [333]

3 years ago

12

According to Boyle’s law, PV= K, what was the volume at the time of the first measurement given the following information? Round

to the nearest mL.
P1=5.42 atm
P2=8.59 atm
V2=527 mL

Mathematics

1 answer:

Temka [501] · Answer 1 · 2022-07-27T11:21:16+03:00

<h2>Hello!</h2>

The answer is:

The first measurement of volume is equal to 835.23 mL.

Boyle's Law equation can be used when the temperature is kept constant, and it establishes a relation between the pressure and volume, showing that when an ideal gas is kept constant, the pressure and volume are inversely proportional.

So, we Boyle's Law equation states that:

$P_{1}V_{1}=P_{2}V_{2}$

Where,

$P_1=FirstPressure\\V_1=FirstVolume\\P_2=NewPressure\\V_2=NewVolume$

Now, if we are looking for the first volume measurement, we need to rewrite the equation as follow:

$P_{1}V_{1}=P_{2}V_{2}\\\\V_{1}=\frac{P_{2}V_{2}}{P_{1}}$

So, substituting the given information and calculating, we have:

$V_{1}=\frac{8.59atm*527mL}{5.42atm}$

$V_{1}=\frac{4526.93atm.mL}{5.42atm}=835.23mL$

Hence, the first measurement of volume is equal 835.23 mL.

Have a nice day!