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Len [333]
3 years ago
12

According to Boyle’s law, PV= K, what was the volume at the time of the first measurement given the following information? Round

to the nearest mL.
P1=5.42 atm
P2=8.59 atm
V2=527 mL
Mathematics
1 answer:
Temka [501]3 years ago
8 0
<h2>Hello!</h2>

The answer is:

The first measurement of volume is equal to 835.23 mL.

<h2>Why?</h2>

Boyle's Law equation can be used when the temperature is kept constant, and it establishes a relation between the pressure and volume, showing that when an ideal gas is kept constant, the pressure and volume are inversely proportional.

So, we Boyle's Law equation states that:

P_{1}V_{1}=P_{2}V_{2}

Where,

P_1=FirstPressure\\V_1=FirstVolume\\P_2=NewPressure\\V_2=NewVolume

Now, if we are looking for the first volume measurement, we need to rewrite the equation as follow:

P_{1}V_{1}=P_{2}V_{2}\\\\V_{1}=\frac{P_{2}V_{2}}{P_{1}}

So, substituting the given information and calculating, we have:

V_{1}=\frac{8.59atm*527mL}{5.42atm}

V_{1}=\frac{4526.93atm.mL}{5.42atm}=835.23mL

Hence, the first measurement of volume is equal 835.23 mL.

Have a nice day!

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