T=(60cos78, 60sin78)
T=(12.47, 58.69)
C=45
d=√((45-12.47)^2+58.69^2)
d≈67.1km
Answer:
3
Step-by-step explanation:
Slope = y2- y1/ x2- x1
= 4 - (-2) / 3 -1
= 4+2/ 2
=6/2 = 3
Answer:
|5| = 5 and |2| = 2 and because 5 > 2, our answer is |5| > |2|.
Given:
Line segment NY has endpoints N(-11, 5) and Y(3,-3).
To find:
The equation of the perpendicular bisector of NY.
Solution:
Midpoint point of NY is




Slope of lines NY is




Product of slopes of two perpendicular lines is -1. So,


The perpendicular bisector of NY passes through (-4,1) with slope
. So, the equation of perpendicular bisector of NY is




Add 1 on both sides.

Therefore, the equation of perpendicular bisector of NY is
.