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3 years ago

If two men can paint two rooms in two hours, how long will it take for one man to paint one room

Mathematics

1 answer:

Mrac [35]3 years ago

6 0

Each room would be 1 hour because it say that two rooms get painted in two hours <span />

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A movie theater charges

KIM [24]

Answer:

it depends how good the food is lol

Step-by-step explanation:

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2 years ago

Help meeeeeeeeeeeeeeeeeeee

Norma-Jean [14]

Answer:

-336/527

Step-by-step explanation:

Trig identities are involved.

tan(2x) = 2tan(x)/(1 -tan(x)²)

Using tan = sin/cos, we can write this in terms of sine and cosine as ...

tan(2x) = (2sin(x)/cos(x))/(1 -sin(x)²/cos(x)²) = 2sin(x)cos(x)/(cos(x)² -sin(x)²)

= 2sin(x)cos(x)/(1 -2sin(x)²)

Now, the cosine can be found from ...

cos(x) = √(1 -sin(x)²)

for sin(θ) = 24/25, cos(θ) = √(1 -(24/25)²) = 7/25 . . . . 1st quadrant angle

Filling in the values in the above identity, we have ...

tan(2θ) = 2(24/25)(7/25)/(1 -2(24/25)²) = 336/-527

tan(2θ) = -336/527

_____

You can use a calculator or estimate that the angle for sin(θ) = 24/25 will be greater than 67.5°, so double the angle will be greater than 135°. (θ ≈ 74°) This means ...

2θ > 135°, so the magnitude of tan(2θ) will be less than 1
2θ is in the 2nd quadrant, so the sign of tan(2θ) will be negative

These observations will help you choose the correct answer without any further math.

8 0

2 years ago

How much would you have to deposit today to have an accumulated amount of $20,000 in 20 years if yearly interest is 4.75% compou

Ivan

Answer:

I think its $95,000

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2 years ago

An experiment is designed to compare the average salaries of employees in a particular position in two competing companies. The

worty [1.4K]

C.
Glad I could help!! ! ^-^

7 0

2 years ago

Read 2 more answers

Suppose the interval [negative 2,0] is partitioned into nequals4 subintervals. What is the subinterval length Upper Delta x?

Maslowich

Answer:

We find the length of each subinterval dividing the distance between the endpoints of the interval by the quantity of subintervals that we want.

Then

Δx= $\frac{0-(-2)}{4}=\frac{2}{4}=\frac{1}{2}$

Now, each $x_i$ is found by adding Δx iteratively from the left end of the interval.

$x_0=-2\\x_1=-2+\frac{1}{2}=\frac{-3}{2}\\x_2=\frac{-3}{2}+\frac{1}{2}=-1\\x_3=-1+\frac{1}{2}=-\frac{1}{2}\\x_4=\frac{-1}{2}+\frac{1}{2}=0$

Each subinterval is

$s_1=[-2,-3/2]\\s_2=[-3/2,-1]\\s_3=[-1,-1/2]\\s_4=[-1/2,0]$

The midpoints of the subintervals are

$m_1=\frac{-2-3/2}{2}=\frac{-7/2}{2}=\frac{-7}{4}\\m_2=\frac{-1-3/2}{2}=\frac{-5/2}{2}=\frac{-5}{4}\\m_3=\frac{-1/2-1}{2}=\frac{-3/2}{2}=\frac{-3}{4}\\m_4=\frac{0-1/2}{2}=\frac{-1}{4}$

The points used for the

1. left Riemann sums are the left endpoints of the subintervals, that is

$x_0=-2, x_1=\frac{-3}{2}, x_2=-1, x_3= \frac{-1}{2}$

2. right Riemann sums are the right endpoints of the subinterval,

$x_1=-\frac{3}{2}, x_2=-1, x_3=-\frac{1}{2}, x_4=0$

3. midpoint Riemann sums are the midpoints of each subinterval

$m_1,m_2,m_3,m_4.$

5 0

3 years ago