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Mekhanik [1.2K]
2 years ago
9

A line passes through the point (-8,3) and has a slope of -3/4. What is this equation in slope intercept form

Mathematics
1 answer:
kupik [55]2 years ago
4 0
I did the math and I believe the answer is, the y-intercept is 12.3.
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When Ryan counted some dimes and quarters he had 196 coins and a total of $39.40. How many coins of each kind does Ryan have?
Nonamiya [84]
Quarters = x
dimes = 196 - x

10(196 - x) + 25x = 3940
1960 - 10x +25x = 3940
1960 + 15x = 3940
15x = 1980
x = 132

169 - 132 = 64

Therefor there are 132 quarters and 64 dimes
6 0
3 years ago
Calculate the sample standard deviation and sample variance for the following frequency distribution of hourly wages for a sampl
lidiya [134]

Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13

x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88

x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63

x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38

x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13

So, the table becomes:

\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}

Next, calculate the mean

\bar x = \frac{\sum fx}{\sum f}

\bar x = \frac{20*9.13 + 38 * 10.88+36*12.63+25*14.38+27*16.13}{20+38+36+25+27}

\bar x = \frac{1845.73}{146}

\bar x = 12.64

Next, the sample variance is:

\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}

So, we have:

\sigma^2 = \frac{20*(9.13-12.63)^2 + 38 * (10.88-12.63)^2 +...........+27 * (16.13 -12.63)^2}{20+38+36+25+27-1}

\sigma^2 = \frac{2393.6875}{145}

\sigma^2 = 16.51

The sample standard deviation is:

\sigma = \sqrt{\sigma^2}

\sigma = \sqrt{16.51}

\sigma = 4.06

6 0
2 years ago
Four people are carpeting a house. Heidi carpets 16 of the house, Lisa carpets 16% of the house, Martina carpets 0.2 of the hous
Alborosie

Answer:

Heidi, Lisa, Jaydie, and Martina

Step-by-step explanation:

16%, 16%, 18%, 20%

5 0
3 years ago
Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet:
Phoenix [80]

6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

<u>Step-by-step explanation:</u>

We have , Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet: 1.25 cups of dry food. Based on these averages . We need to find  how many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks . We need to find how much they eat for 14 days as:

Trenton's pet: 4/5 cup of dry food•

With 4/5 per day , for 14 days :

⇒ 14(\frac{4}{5} )

⇒ 14(0.8 )

⇒ 11.2

Maria's pet: 1.25 cups of dry food.

With 1.25 per day , for 14 days :

⇒ 14(1.25 )

⇒ 17.5

Subtracting Maria's - Trenton's :

⇒ 17.5-11.2=6.3

That means , 6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

3 0
3 years ago
Help please, I’m way too stressed and can’t remember any math:((
Leviafan [203]

Answer:

its 400 cuz 0.1 is tenth

Step-by-step explanation:

6 0
3 years ago
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