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tatiyna
2 years ago
14

Triangle ABC is graphed on a coordinate grid with vertices at A (-2, -4), B (2, -4) and C (0, 2). Triangle ABC is dilated by a s

cale factor of x with the origin as the center of dilation to create triangle A’B’C with the vertices A’ (-1, -2), B’(1, -2), C’ (0, 1).
Which rule best represents the dilation that was applied to Triangle ABC to create A’B’C’?

(x, y) (2x, 2y)

(x, y) (0.2x, 0.2y)

(x, y) (12x, 12y)

(x, y) (14x, 14y)
Mathematics
1 answer:
Papessa [141]2 years ago
6 0

Answer:

The rule which best represents the dilation that was applied to Triangle ABC to create A’B’C’ will be:

(x, y) → (1/2x, 1/2y)

Step-by-step explanation:

Given the vertices of a triangle

  • A(-2, -4)
  • B(2, -4)
  • C(0, 2)

After the dilation, the vertices of an image triangle be

  • A' (-1, -2)
  • B '(1, -2)
  • C' (0, 1)

If we closely observe, we can notice that the image triangle vertices A'B'C' are half of the original triangle ABC.

i.e. (x, y) → (1/2x, 1/2y)

verification

A(-2, -4) → A'(-2/2, -4/2) = A'(-1, -2)

B(2, -4) → B'(2/2, -4/2) = B'(1, -2)

C(0, 2) → C'(0/2, 2/2) = C'(0, 1)

Thus, it is verified and we conclude that the rule which best represents the dilation that was applied to Triangle ABC to create A’B’C’ will be:

  • (x, y) → (1/2x, 1/2y)
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\text{ The value of m is equal to 3.625 or }\frac{29}{8} \text{ or } 3\frac{5}{8}

<em><u>Solution:</u></em>

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<em><u>Let us first convert the mixed fraction to improper fraction</u></em>

Steps to follow:

Divide the numerator by the denominator.

Write down the whole number answer.

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