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wariber [46]
3 years ago
10

Which of the following is a form of intrapersonal communication?

Computers and Technology
2 answers:
Citrus2011 [14]3 years ago
7 0
Intrapersonal communication is you are also a sender and receiver within yourself. For example your inner thought, daydream, and private diaries.
Umnica [9.8K]3 years ago
4 0

The answer is C: Writing a diary

Intrapersonal communication is the communication with one’s self. This type of communication may include self-task, visualization, acts of imagination and sometimes recall and memory. You sit down and write notes on a diary about events that happened in the past. What comes to mind? Sounds, sights, scents?  This type of communication is taking place within the individual since he or she is alone and thinking to himself or herself.


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Manuel is working on a project in Visual Studio. He wants to keep this program showing on the entire desktop, but he also needs
patriot [66]

Answer:

d. Task View

Explanation:

Based on the scenario being described within the question it can be said that the best feature for this would be the Windows 10 task view. This is a task switcher and  virtual desktop system included in the Windows 10 operating system, and allow the individual user to quickly locate, manage, open or hide different windows/tasks. Such as having several projects open in different monitors running at the same time.

3 0
4 years ago
Consider the classes below:
jeka57 [31]

Answer:

Hi!

The correct answer is d. Neither (a) nor (b) is true.

Explanation:

First, you have to know what the scripts intend to do, and they are counting from 1 to 10 in both cases.

Table of results of class TestA at end of each iteration:

[j = 0,  counter =  1]

[j = 10,  counter =  2]

[j = 20,  counter =  3]

[j = 30,  counter =  4]

[j = 40,  counter =  5]

[j = 50,  counter =  6]

[j = 60,  counter =  7]

[j = 70,  counter =  8]

[j = 80,  counter =  9]

[j = 90,  counter =  10]

Table of results of class TestB at end of each iteration:

[j = 10,  counter =  1]

[j = 9,  counter =  2]

[j = 8,  counter =  3]

[j = 7,  counter =  4]

[j = 6,  counter =  5]

[j = 5,  counter =  6]

[j = 4,  counter =  7]

[j = 3,  counter =  8]

[j = 2,  counter =  9]

[j = 1,  counter =  10]

That's why a) and b) are false.

Maybe you want to know why using pre increments on class TestB doesn't affect the loop. The reason is that when enters in a loop, first checks the test condition and takes the decision if true or false, and last executes the incrementation step.

7 0
3 years ago
Someone, please answer this.
Sav [38]

Answer: A loop will continue running until the defined condition returns false . ... You can type js for , js while or js do while to get more info on any of these. ... initialization - Run before the first execution on the loop. ... But it can be used to decrement a counter too. statement - Code to be repeated in the loop.

Explanation:

7 0
3 years ago
What stage of software development incorporates planning to help make changes in the project plan based of reviews
larisa86 [58]

Answer:

A

Explanation:

8 0
3 years ago
// This pseudocode is intended to display // employee net pay values. All employees have a standard // $45 deduction from their
Vikki [24]

Answer:

C++ code is given below

Explanation:

#include<iostream>

#include <cstring>

using namespace std;

int housekeeping(string EOFNAME);

int mainLoop(string name,string EOFNAME);

int finish();

void main()

{

  string name;

  string EOFNAME = "ZZZZ";

  cout << "enter the name" << endl;

  cin >> name;

  if (name != EOFNAME)

  {

      housekeeping(EOFNAME);

  }

  if (name != EOFNAME)

  {

      mainLoop(name , EOFNAME);

  }

  if (name != EOFNAME)

  {

      finish();

  }

  system("pause");

}

int housekeeping(string EOFNAME)

{  

  cout << "enter first name " << EOFNAME << " to quit " << endl;

  return 0;

}

int mainLoop(string name, string EOFNAME)

{  

  int hours;

  int rate,gross;

  int DEDUCTION = 45;

  int net;

  cout << "enter hours worked for " << name << endl;

  cin >> hours;

  cout << "enter hourly rate for " << name << endl;

  cin >> rate;

  gross = hours*rate;

  net = gross - DEDUCTION;

  if (net > 0)

  {

      cout << "net pay for " << name << " is " << net << endl;

  }

  else

  {

      cout << "dedections not covered.net is 0.";

  }

  cout << "enter next name or " << EOFNAME << " to quit" << endl;

  cin >> name;

  return 0;

}

int finish()

{

  cout << "end of job"<<endl;

  return 0;

}

3 0
4 years ago
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