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3 years ago

Multiply: (5t – 4)(4t + 5)

Mathematics

2 answers:

AnnZ [28]3 years ago

5 0

<span>The answer is this 20t2 + 9t – 20. Go look up a video for foiling </span>

ch4aika [34]3 years ago

3 0

<h2>Answer:</h2>

The product of the expression is:

$20t^2+9t-20$

<h2>Step-by-step explanation:</h2>

We have to find the product of two algebraic expressions which are given in terms of variable t as:

$(5t-4)(4t+5)$

We know that the product of two linear function will result in a quadratic equation i.e. a polynomial of degree 2.

We find the product as follows:

$(5t-4)(4t+5)=5t(4t+5)-4(4t+5)\\\\\\i.e.\\\\\\(5t-4)(4t+5)=20t^2+25t-16t-20\\\\\\i.e.\\\\(5t-4)(4t+5)=20t^2+9t-20$

Hence, the product is:

$20t^2+9t-20$

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20 POINTS AND BRAINLIEST FOR CORRECT ANSWER! A cone with height h and radius r has volume V = 13πr2h. If a certain cone with a h

lozanna [386]

Answer:

If a certain cone with a height of 9 inches has volume V = 3πx2 + 42πx + 147π, what is the cone’s radius r in terms of x?

Step-by-step explanation:

V = 3πx2 + 42πx + 147π

V=3π(x2 + 14x +49)

9.42(x2 + 14x +49)

9.42(x2 + 14x +14) -14 + 49= 0

9.42(x + 7)^2 + 35= 0

9.42(9.42(x + 7)^2 = - 35)9.42

(x + 7)^2 = - 35/9.42)

√(x + 7)^2=√- 35/9.42

x + 7 = - 1.927

x= - 1.927 - 7

x= - 8.927

V = 3π(- 8.927)^2 + 42π(- 8.927) + 147π

V=750.69 - 1177.29 + 461.58

h= 9 inches

V = 13πr2h

34.98 = 13(3.14) (r^2) (h)

34.98 = 40.82 (r^2) 9

34.98 = 367.38 r^2

34.98/ 367.38 = 367.38 r^2/ 367.38

0.095= r^2

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3 years ago

Find the area of a circle with the circumference 32pi

Stella [2.4K]

Answer:

A=πr2

C=2πr

Solving forA

A=C2

4π=322

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3 years ago

WILL MARK BRAINLEST IF CORRECT HELP ME OUT

sveta [45]

Answer:

x = 12

Step-by-step explanation:

Equation: 0.52(x) + 0.72(4) = 0.57(x + 4)

0.52(x) + 0.72(4) = 0.57(x + 4) $\longmapsto$ Multiply

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x = 12

-Chetan K

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2 years ago

−2/3(3x−4)+3x=5/6 whoever gets right gets brainlyest

REY [17]

−2/3(3x−4)+3x=5/6

= -11/6

7 0

3 years ago

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Identify any solutions to the system given below. 2x + y = 5 3y = 15 – 6x (6, –7) (2, 1) (–2, –9) (–4, 13)

sashaice [31]

Answer:

The answer (2, 1), (-4,13), (6,-7)

Step-by-step explanation:

Consider 2x+y=5 as equation 1, and 3y=15-6x as equation 2

1. Substituting values x and y with x=2 and y=1 as given by the coordinates (2,1)

Equation 1

2(2)+1=5 therefor it holds

Equation 2

3(1)=15-(6×2) also holds

2. Substituting values x and y with x=6 and y=-7 as given by the coordinates (6,-7)

Equation 1

2(6)+(-7)=5

5=5 holds

Equation 2

3(-7)=15-(6×6)

-21=-21 also holds

3. Substituting values x and y with x=-4 and y=13 as given by the coordinates (-4,13)

Equation 1

2(-4)+13=13-8=5 holds

Equation 2

3(13)=15-(6×-4)=39 also holds

4. Substituting values x and y with x=-2 and y=-9 as given by the coordinates (-2,-9)

Equation 1

2(-2)+(-9)=-4-9=-13≠5 does not hold

Equation 2

3(-9)≠15-(6×-2)

-27≠27 does not hold

The coordinates (2,1), (-4,13) and (6,-7) can be used as solutions to the system given

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3 years ago

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