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3 years ago

Multiply: (5t – 4)(4t + 5)

Mathematics

2 answers:

AnnZ [28]3 years ago

5 0

<span>The answer is this 20t2 + 9t – 20. Go look up a video for foiling </span>

ch4aika [34]3 years ago

3 0

<h2>Answer:</h2>

The product of the expression is:

$20t^2+9t-20$

<h2>Step-by-step explanation:</h2>

We have to find the product of two algebraic expressions which are given in terms of variable t as:

$(5t-4)(4t+5)$

We know that the product of two linear function will result in a quadratic equation i.e. a polynomial of degree 2.

We find the product as follows:

$(5t-4)(4t+5)=5t(4t+5)-4(4t+5)\\\\\\i.e.\\\\\\(5t-4)(4t+5)=20t^2+25t-16t-20\\\\\\i.e.\\\\(5t-4)(4t+5)=20t^2+9t-20$

Hence, the product is:

$20t^2+9t-20$

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Read 2 more answers

A quadratic function is a function of the form y=ax^2+bx+c where a, b, and c are constants. Given any 3 points in the plane, the

pochemuha

Answer:

The quadratic function whose graph contains these points is $y=-x^{2}-2x-2$

Step-by-step explanation:

We know that a quadratic function is a function of the form $y=ax^{2}+bx+c$ . The first step is use the 3 points given to write 3 equations to find the values of the constants <em>a</em>,<em>b</em>, and <em>c</em>.

Substitute the points (0,-2), (-5,-17), and (3,-17) into the general form of a quadratic function.

$-2=a*0^{2}+b*0+c\\c=-2$

$-17=a*-5^{2}+b*-5+c\\c=-25a+5b-17$

$-17=a*3^{2}+b*3+c\\ c=-9a-3b-17$

We can solve these system of equations by substitution

Substitute $c=-9a-3b-17$

$-9a-3b-17=25a+5b-17\\-9a-3b-17=-2$

Isolate a for the first equation

$-9a-3b-17=-25a+5b-17\\a=\frac{b}{2}$

Substitute $a=\frac{b}{2}$ into the second equation

$-9\left(-\frac{b}{2}\right)-3b-17=-2$

Find the value of b

$-9\left(-\frac{4b}{17}\right)-3b-17=-2\\ b=-2$

Find the value of a

$a=\frac{b}{2}\\ a=-1$

The solutions to the system of equations are:

b=-2,a=-1,c=-2

So the quadratic function whose graph contains these points is

$y=-x^{2}-2x-2$

As you can corroborate with the graph of this function.

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3 years ago