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Verdich [7]
3 years ago
6

Multiply: (5t – 4)(4t + 5)

Mathematics
2 answers:
AnnZ [28]3 years ago
5 0
<span>The answer is this 20t2 + 9t – 20. Go look up a video for foiling </span>
ch4aika [34]3 years ago
3 0
<h2>Answer:</h2>

The product of the expression is:

            20t^2+9t-20

<h2>Step-by-step explanation:</h2>

We have to find the product of two algebraic  expressions which are given in terms of variable t  as:

           (5t-4)(4t+5)

We know that the product of two linear function will result in a quadratic equation i.e. a polynomial of degree 2.

We find the product as follows:

(5t-4)(4t+5)=5t(4t+5)-4(4t+5)\\\\\\i.e.\\\\\\(5t-4)(4t+5)=20t^2+25t-16t-20\\\\\\i.e.\\\\(5t-4)(4t+5)=20t^2+9t-20

Hence, the product is:

        20t^2+9t-20

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What is 5682 divided by 4
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5682 divided by 4 is 1420 remainder 2 Hope that helped Have a good day! :-)
6 0
3 years ago
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At the end of a snow storm, Audrey saw there was a lot of snow on her front lawn. The temperature increased and the snow began t
zalisa [80]

Answer:

s = 2t

Step-by-step explanation:

At the end of a snow storm, Audrey saw there was a lot of snow on her front lawn. The temperature increased and the snow began to melt at a steady rate. There was a depth of 10 inches of snow on the lawn when the storm ended and then it started melting at a rate of 2 inches per hour. Write an equation for S, in terms of t, representing the depth of snow on Audreys lawn, in inches, t hours after the snow stopped falling.

2 inches = 1 hour

10 inches = x hour

2x = 10

x = 10/2

x = 5

Creating an equation

S ∝ t

S = kt

k = s/t

k = 2/1

k = 2

The equation for S, in terms of t, representing the depth of snow on Audreys lawn, in inches, t hours after the snow stopped falling is

S = 2t

8 0
3 years ago
Find the area of the polygon ​
katrin [286]

Answer:

just add the area of the triangle(formula 1/2bh) and the area of the square(formula bh)

so 1/2(6*height)+8*7

Step-by-step explanation:

5 0
4 years ago
What is 2log 9 in simplest form?
Mamont248 [21]

Answer:

1.90

hope it helps you

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3 years ago
A geometric sequence is defined by the equation an = (3)3 − n.
Delvig [45]
PART A

The geometric sequence is defined by the equation

a_{n}=3^{3-n}

To find the first three terms, we put n=1,2,3

When n=1,

a_{1}=3^{3-1}

a_{1}=3^{2}

a_{1}=9
When n=2,

a_{2}=3^{3-2}
a_{2}=3^{1}

a_{2}=3

When n=3

a_{3}=3^{3-3}

a_{3}=3^{0}
a_{1}=1
The first three terms are,

9,3,1

PART B

The common ratio can be found using any two consecutive terms.

The common ratio is given by,
r= \frac{a_{2}}{a_{1}}
r = \frac{3}{9}

r = \frac{1}{3}

PART C

To find
a_{11}

We substitute n=11 into the equation of the geometric sequence.

a_{11} = {3}^{3 - 11}

This implies that,

a_{11} = {3}^{ - 8}

a_{11} = \frac{1}{ {3}^{8} }

a_{11}=\frac{1}{6561}
4 0
3 years ago
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