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Evgesh-ka [11]
2 years ago
9

8 x 10*-3

Mathematics
1 answer:
NARA [144]2 years ago
7 0

Answer:

\huge\boxed{2\times10^3}

Step-by-step explanation:

(8\times10^{-3})\div(4\times10^{-6})=\dfrac{8\times10^{-3}}{4\times10^{-6}}=\dfrac{8}{4}\times10^{-3-(-6)}=2\times10^{-3+6}=2\times10^3

Used:

\dfrac{a^n}{a^m}=a^{n-m}\ \text{for}\ a\neq0

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The wheels on a car have a diameter of 28 inches. How many full revolutions will the wheels need to make to travel 200 feet?
rodikova [14]
Here we're interested in the circumference:  C = pi*d.  In this case C = 3.14*(28 inches) = 88 inches. 

Now divide this 88 inches into 200 feet to get the # of revolutions ncessary to travel 200 feet.

200 feet     12 in
------------ * --------- = 2400 inches
       1           1 ft

2400 inches
----------------------- = 27.2 revolutions   (answer)
[ 88 inches/ rev ]
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3 years ago
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3 years ago
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Zanzabum
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