8 x 10*-3

Mathematics

1 answer:

NARA [144]2 years ago

7 0

Answer:

$\huge\boxed{2\times10^3}$

Step-by-step explanation:

$(8\times10^{-3})\div(4\times10^{-6})=\dfrac{8\times10^{-3}}{4\times10^{-6}}=\dfrac{8}{4}\times10^{-3-(-6)}=2\times10^{-3+6}=2\times10^3$

Used:

$\dfrac{a^n}{a^m}=a^{n-m}\ \text{for}\ a\neq0$

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Answer:

B $(x,y) \rightarrow \left(\frac{5}{2}x,\frac{5}{2}y\right)$

Step-by-step explanation:

Dilations

Given a point A(x,y) and a scale factor k the dilated image of A, called A' is calculated as A'=(kx,ky), assuming the same scale factor is applied in both axes.

The pentagon ABCDE was dilated to create pentagon A'B'C'D'E'. To find the dilaton rule used, we must find two clear points where the coordinates of both axes can be easily read from the graph.

Point C(-2,0) maps to C'(-5,0). This gives us the scale factor for the x-axis of -5/(-2)= 5/2.

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Thus, the rule to dilate the pentagon is:

B $\mathbf{(x,y) \rightarrow \left(\frac{5}{2}x,\frac{5}{2}y\right)}$