2 years ago

(b+3g)a=9. Solve for a

Mathematics

1 answer:

Lynna [10]2 years ago

7 0

Answer:

A= ______

b+3g

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Find the equation of a parabola that has a vertex of (-2,-3) and contains the point (4,1)

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$\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
\boxed{y=a(x- h)^2+ k}\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{-2}{ h},\stackrel{-3}{ k})\\\\
-------------------------------\\\\
\begin{cases}
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\end{cases}\implies y=a[x-(-2)]^2-3\implies y=a(x+2)^2-3
\\\\\\
\textit{we also know that }
\begin{cases}
x=4\\
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\end{cases}\implies 1=a(4+2)^2-3
\\\\\\
4=36a\implies \cfrac{4}{36}=a\implies \cfrac{1}{9}=a
\\\\\\
therefore\qquad \boxed{y=\cfrac{1}{9}(x+2)^2-3}$

$\bf y=\cfrac{1}{9}(x+2)^2-3\implies y=\cfrac{1}{9}(x^2+4x+4)-3
\\\\\\
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