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Irina-Kira [14]
3 years ago
6

PLZ HELP IF WRONG ILL REPORT

Mathematics
2 answers:
dimulka [17.4K]3 years ago
7 0
I HONESTLY WOULD THINK THIS COULD BE BIAS ONLY BECAUSE DIFFERENT OPINION ARE INCLUDED BUT AT THE SAME TIME BESTBUY NEVER SAID ANYTHING ABIUT THEM HATING BESTBUY
kvv77 [185]3 years ago
6 0

Answer:

The store calls and asks every 4th person who bought a television within the past year whether he or she likes it.

<u>It is biased because opinion was shared..</u>

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Using the given zero, find one other zero of f(x). Explain the process you used to find your solution.
IRISSAK [1]

Answer:

One other zero is 2+3i

Step-by-step explanation:

If 2-3i is a zero and all the coefficients of the polynomial function is real, then the conjugate of 2-3i is also a zero.

The conjugate of (a+b) is (a-b).

The conjugate of (a-b) is (a+b).

The conjugate of (2-3i) is (2+3i) so 2+3i is also a zero.

Ok so we have two zeros 2-3i and 2+3i.

This means that (x-(2-3i)) and (x-(2+3i)) are factors of the given polynomial.

I'm going to find the product of these factors (x-(2-3i)) and (x-(2+3i)).

(x-(2-3i))(x-(2+3i))

Foil!

First: x(x)=x^2

Outer: x*-(2+3i)=-x(2+3i)

Inner:  -(2-3i)(x)=-x(2-3i)

Last:  (2-3i)(2+3i)=4-9i^2 (You can just do first and last when multiplying conjugates)

---------------------------------Add together:

x^2 + -x(2+3i) + -x(2-3i) + (4-9i^2)

Simplifying:

x^2-2x-3ix-2x+3ix+4+9  (since i^2=-1)

x^2-4x+13                     (since -3ix+3ix=0)

So x^2-4x+13 is a factor of the given polynomial.

I'm going to do long division to find another factor.

Hopefully we get a remainder of 0 because we are saying it is a factor of the given polynomial.

                x^2+1

              ---------------------------------------

x^2-4x+13|  x^4-4x^3+14x^2-4x+13                    

              -( x^4-4x^3+ 13x^2)

            ------------------------------------------

                                 x^2-4x+13

                               -(x^2-4x+13)

                               -----------------

                                    0

So the other factor is x^2+1.

To find the zeros of x^2+1, you set x^2+1 to 0 and solve for x.

x^2+1=0

x^2=-1

x=\pm \sqrt{-1}

x=\pm i

So the zeros are i, -i , 2-3i , 2+3i

7 0
3 years ago
Someone please help me 3#
tensa zangetsu [6.8K]

Answer:

e

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What Is k 5(3-2k)=2k+39​
Hatshy [7]

Answer:

k = -2.

Step-by-step explanation:

5(3 - 2k) = 2k + 39     Distribute the 5 over the parentheses:

15 - 10k = 2k + 39

15 - 39 = 2k + 10k

12k = -24

k = -2.

8 0
3 years ago
What is the value of x?
Blizzard [7]

check the picture below.

so, when we have a line from a 90° angle running perpendicular to the opposite side, like in this case, we end up with three similar triangles, a large one containing the other two, a medium and a small one.

now, using the sides proportions as you see there, of the small and large one, we get that much.

3 0
3 years ago
9. What is the tan(90-x)?
Aleonysh [2.5K]

\\ \sf\longmapsto tanx=\dfrac{Perpendicular}{Base}

\\ \sf\longmapsto tanx=\dfrac{4}{3}

\\ \sf\longmapsto x=tan^{-1}(4/3)

\\ \sf\longmapsto x=53°

\\ \sf\longmapsto tan(90-x)

\\ \sf\longmapsto cotx

\\ \sf\longmapsto cot53

\\ \sf\longmapsto \dfrac{3}{4}

\\ \sf\longmapsto 0.75

6 0
2 years ago
Read 2 more answers
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