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Inga [223]
2 years ago
14

consider the graph of the linear equatioin 2x-5y=10. the x intercept is, the y intercept is, the slope is

Mathematics
1 answer:
MAXImum [283]2 years ago
3 0

Answer:

x intercept = (5, 0)

y intercept = (0, -2)

slope = 2/5

Step-by-step explanation:

2x - 10 = 5y

\frac{2x-10}{5} = y

\frac{2}{5}x -2 = y

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At sunset the temperature was 4 dgrees. the next morning at sunset it was -7 degrees. what is the difference betweeen these temp
DedPeter [7]

The difference between these temperatures for the sunset is found as 11 degrees.

<h3>What is temperature difference?</h3>

In science, the term Delta T (ΔT) refers to the temperature between two measuring points. The temperature varies according to time and/or location.

Some key features regarding the temperature difference are-

  • Merus, for example, uses it to assess the effectiveness of such a heat exchanger.
  • Or to evaluate the effectiveness of a heating or cooling system.
  • A fourth letter of a Greek alphabet is, (Δ). Whereas is the capital letter symbol and the lower case letter.
  • The sign is also used in mathematics. Describes the "difference" between any two changeable quantities. T is a value in a process that represents a difference between two observed temperatures.

Now, according to the question;

Let the initial temperature be 'T' = 4 degrees.

Let the final temperature be 't' = -7 degrees.

Therefore, the temperature difference is;

ΔT =  T - t

     = 4 - (-7)

     = 4 + 7

ΔT = 11

Therefore, the difference between these temperatures is 11 degrees.

To know more about the temperature difference, here

brainly.com/question/24746268

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1 year ago
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If an average walk to the gas station is 15 minutes. why has my dad been gone for 11 years?
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Find all of the points of the form (x −1) which are 4 unit from the point (3,2)
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Answer:

(3+2\sqrt{2},2+2\sqrt{2}),(3-2\sqrt{2},2-2\sqrt{2})

Step-by-step explanation:

Points\ are\ of\ the\ form\ (x,x-1)\\\\Distance\ of\ these\ points\ from\ (3,2)=4\\\\\sqrt{(x-3)^2+(x-3)^2}=4\\\\\sqrt{(x-3)^2+(x-1-2)^2}=4\\\\\sqrt{2(x-3)^2}=4\\\\2(x-3)^2=16\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ square\ both\ the\ sides\\\\(x-3)^2=\frac{16}{2}\\\\(x-3)^2=8\\\\(x-3)=\pm 2\sqrt{2}\ \ \ \ \ \ \ \ \ \ \ square\ root\ both\ the\ sides\\\\x=3\pm 2\sqrt{2}\\\\When\ x=3+2\sqrt{2}\ \ \Rightarrow x-1=3+2\sqrt{2}-1=2+2\sqrt{2}\\\\When\ x=3-2\sqrt{2}\ \ \Rightarrow x-1=3-2\sqrt{2}-1=2-2\sqrt{2}

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