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Keith_Richards [23]
3 years ago
10

The speed limit is 55 minutes per hr. write an inequalit to represent the speed limit.

Mathematics
1 answer:
anygoal [31]3 years ago
5 0
Answer: Either x \le 55 or 0 \le x \le 55 depending on your teacher's preference. See the note at the bottom for more info. 

=====================================

Let x be the speed limit. It is simply a placeholder. Think of it as a box with the number inside. We don't know what the number is, but we know that the largest it can be is 55. It cannot be larger than 55.

So x can be equal to 55 or it can be smaller

Put another way, x is less than or equal to 55 which is written as x \le 55 (on the keyboard you would type " x <= 55 " without quotes). 

---------------------------------------

Note: since negative speeds make no sense, we also must imply that x can't be negative. Your teacher may want you to write this in to clearly state it. If so, then you would also have x \ge 0 which when combined with the first inequality, you get this compound inequality 0 \le x \le 55 (basically saying "x is some speed between 0 and 55 mph"). This very clearly states the boundaries on what x can be. Though your teacher may want you to stick to the first format as its simpler. 
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36 first-graders and 14 other students attended a school assembly. What percentage of the students at the assembly were first-gr
dimaraw [331]

Answer: 18%

Step-by-step explanation: Add 36 + 14 = 50

Then 36*50/100=18

5 0
3 years ago
Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.
Gnesinka [82]

Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, \overline{CP} ⊥ \overline{AM}, AP = 9, and PM = 16

\overline{AC}² + \overline{CM}² = \overline{AM}²

\overline{AM} = \overline{AP} + PM = 9 + 16 = 25

\overline{AM} = 25

\overline{AC}² = \overline{AP}² + \overline{CP}² = 9² +  \overline{CP}²

∴ \overline{AC}² = 9² +  \overline{CP}²

Similarly we get;

\overline{CM}² = 16² + \overline{CP}²

Therefore, we get;

\overline{AC}² + \overline{CM}² = 9² +  \overline{CP}² + 16² + \overline{CP}² = \overline{AM}² = 25²

2·\overline{CP}² = 25² - (9² + 16²) = 288

\overline{CP}² = 288/2 = 144

\overline{CP} = √144 = 12

From \overline{AC}² = 9² +  \overline{CP}², we get

\overline{AC} = √(9² +  12²) = 15

\overline{AC} = 15

From, \overline{CM}² = 16² + \overline{CP}², we get;

\overline{CM} = √(16² + 12²) = 20

\overline{CM} = 20.

3 0
3 years ago
Thank you for helping me :D
Aleonysh [2.5K]
The answer is both sets of statistics give the same information:

First, find the mean: 2 • 5 = 10, 3 • 4 = 12, and 10 • 1 = 10

10 + 12 + 10 = 32

Ten dots altogether : 32 ÷ 10 = 3.2

Mean = 3.2

Second, find the median: 2, 2, 2, 2, 2, 3, 3, 3, 3, 10

2, 2, 2, 2, <em>2, 3,</em> 3, 3, 3, 10

2 + 3 = 5

5 / 2 = 2.5

Median - 2.5
3 0
3 years ago
WILL GIVE BRAINLIEST IF CORRECT!!!
Delicious77 [7]
21/2 or 10 1/2
Explanation:
8 3/4 is the same as 35/4

so Darcy harvests 35/4 per 5/6 hours
to figure out how much is harvested in one hour, you divide the amount harvested by the amount of hours taken to harvest it.
35/4 ÷ 5/6 =35/4 × 6/5

35/4 × 6/5 = 7/2 × 3/1 = 21/2

so the answer is 21/2 or 10 1/2
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