Before:
The number of goats =60%
The number of cows = 100%
Using ratio
Cows : Goats
60 : 100 reduced to simplest term
C:G
3:5
After
The number of cows = 100%
The number of goats = 60%
Using ratio
C:G
100:60 reduced to simplest term
C:G
5:3
Number of cows remained constant. Therefore find the common multiple.
Before
C:G
15:25
After
C:G
15:9
Find the difference in the units of goats
(a)25 - 19= 16
16 units =80
1 unit = 5
15 units (cows) = 5 x 15 = 75
There were 75 cows.
(B)
Number of goats at first
25 units = 5 x 25 = 125
Therefore percentage= 80/125 x 100
= 64%
Answer:
5 to 6 times
Step-by-step explanation:
Just look at the biggest bar.
Ok so the answer is <span>Students in Class 1 took less time to complete the test than students in Class 2, and their times were more variable. Im 10000% positive</span>
Answer:
A. By the Side-Side-Side (SSS) Congruence Theorem, ΔABC ≅ ΔDEF.
B. 
Step-by-step explanation:
a. From the diagram given, it shows that all three sides of ∆ABC are congruent to all the three corresponding sides of ∆DEF.
Therefore, by the Side-Side-Side (SSS) Congruence Theorem, ΔABC ≅ ΔDEF.
b. The sides that are congruent in the ∆s given that applies to the SSS Congruence Theorem are:
