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makvit [3.9K]
2 years ago
15

What is the probability that a point chosen at random in the given figure will be inside the larger square and outside the small

er square? Enter your answer, as a fraction in simplest form, in the box. P(inside larger square and outside smaller square) = $\text{Basic}$ $x$$y$$x^2$$\sqrt{ }$$\frac{x}{ }$ $x\frac{ }{ }$ $x^{ }$$x_{ }$$\degree$$\left(\right)$$\abs{ }$$\pi$$\infty$ A square with a side length of 7 centimeters is within a larger square with a side length of 10 centimeters. The sides of the inner square do not touch the sides of the outer square.
Mathematics
1 answer:
liraira [26]2 years ago
5 0

Answer:

  • 51/100

Step-by-step explanation:

<em>The probability that a point chosen at random in the given figure will be inside the larger square and outside the smaller square</em> is equal to the ratio of the area of interest to the total area:

<em>P(inside larger square and outside smaller square)</em> = area of interest / total area

<em>P(inside larger square and outside smaller square)</em> = area inside the larger square and outside the smaller square / area of the larger square

<u>Calculations:</u>

<u />

1. <u>Area inside the larger square</u>: side² = (10 cm)² = 100 cm²

2. <u>Area inside the smaller square </u>= side² = (7cm)² = 49 cm²

3. <u>Area inside the larger square and outside the smaller square</u>

  • 100 cm² - 49 cm² = 51 cm²

4.<u> P (inside larger square and outside smaller squere)</u>

  • 51 cm² / 100 cm² = 51/100
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Work Shown:

The green triangle in the back has height 2.6 and an unknown base x. Half of this is x/2, which I'll call y. So y = x/2.

The green triangle in the back is split along the vertical dotted line to get two right triangles. The base of each right triangle is y = x/2.

Use the Pythagorean theorem to find y. Use that to find x

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So far we've only considered the triangular faces. There are 3 more faces which are the rectangular sides. These are known as the lateral sides.

One way to get the lateral surface area is to multiply the perimeter of the triangle by the depth of the prism

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surface area = (9.70047416) + (83.681660216)

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