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makvit [3.9K]
3 years ago
15

What is the probability that a point chosen at random in the given figure will be inside the larger square and outside the small

er square? Enter your answer, as a fraction in simplest form, in the box. P(inside larger square and outside smaller square) = $\text{Basic}$ $x$$y$$x^2$$\sqrt{ }$$\frac{x}{ }$ $x\frac{ }{ }$ $x^{ }$$x_{ }$$\degree$$\left(\right)$$\abs{ }$$\pi$$\infty$ A square with a side length of 7 centimeters is within a larger square with a side length of 10 centimeters. The sides of the inner square do not touch the sides of the outer square.
Mathematics
1 answer:
liraira [26]3 years ago
5 0

Answer:

  • 51/100

Step-by-step explanation:

<em>The probability that a point chosen at random in the given figure will be inside the larger square and outside the smaller square</em> is equal to the ratio of the area of interest to the total area:

<em>P(inside larger square and outside smaller square)</em> = area of interest / total area

<em>P(inside larger square and outside smaller square)</em> = area inside the larger square and outside the smaller square / area of the larger square

<u>Calculations:</u>

<u />

1. <u>Area inside the larger square</u>: side² = (10 cm)² = 100 cm²

2. <u>Area inside the smaller square </u>= side² = (7cm)² = 49 cm²

3. <u>Area inside the larger square and outside the smaller square</u>

  • 100 cm² - 49 cm² = 51 cm²

4.<u> P (inside larger square and outside smaller squere)</u>

  • 51 cm² / 100 cm² = 51/100
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