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lozanna [386]
3 years ago
7

Write a 3-digit number using digit 2,9,4. Draw a quick Picture to show the value of your number

Mathematics
2 answers:
Tcecarenko [31]3 years ago
5 0
Number- 429
Four hundreds
Twenty tens
Nine ones
wlad13 [49]3 years ago
4 0
294

You can draw 2 blocks representing two one hundreds.
Draw 9 ten columns.
Draw 4 one squares.
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How can you use doubles when multiplying with 4 to find 4x8
pshichka [43]
4 = 2 * 2

Multiplying by 2 is the same a doubling.
Since 4 is 2 * 2, to multiply a number by 4, double the number twice.

Example:
What is 4 * 100?
Double 100 to get 200.
Double 200 to get 400.
Therefore, 4 * 100 = 400.
By doubling twice, we do the same as multiplying by 4.
4 0
3 years ago
PLEASE HELP!!<br> How many solutions can be found for the equation −4x − 11 = 2(x − 3x) + 13?
PilotLPTM [1.2K]

Answer: No~Solutions

Step-by-step explanation:

Let's factor then solve to find the complex solutions.

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : -4x-11=2(x-3x)+13

Equations that are never true:

1.1     ~~~~ Solve :    -24   =  0

This equation has no solution.

A non-zero constant never equals zero.

<u><em>Therefore your answer is </em></u>No~Solution

3 0
2 years ago
What percent is 350 from 125
natulia [17]

Answer:

35.71

Step-by-step explanation:

6 0
3 years ago
dan and miquel are working on the same homework assignment.dan finished 1/4 of the assignment.miquel has finished 3/4 of the ass
stira [4]
Miguel has finished the homework assignment first.
6 0
3 years ago
Read 2 more answers
The attention span of children (ages 3 to 5) is claimed to be Normally distributed with a mean of 15 minutes and a standard devi
Agata [3.3K]

Answer:

If the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 minutes

Sample size, n = 10

Alpha, α = 0.05

Population standard deviation, σ = 4 minutes

First, we design the null and the alternate hypothesis

H_{0}: \mu = 15\text{ minutes}\\H_A: \mu > 15\text{ minutes}

Since the population standard deviation is given, we use one-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Now, z_{critical} \text{ at 0.05 level of significance for one tail} = 1.64

Thus, we would reject the null hypothesis if the z-statistic is greater than this critical value.

Thus, we can write:

z_{stat} = \displaystyle\frac{\bar{x} - 15}{\frac{4}{\sqrt{10}} } > 1.64\\\\\bar{x} - 15>1.64\times \frac{4}{\sqrt{10}}\\\bar{x} - 15>2.07\\\bar{x} > 15+2.07\\\bar{x} > 17.07

Thus, the decision rule would be if the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

6 0
4 years ago
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