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Kaylis [27]
3 years ago
10

A used car was purchased in July 1999 for $11,900. If the car depreciates 13% of it's value each year, what is the value of the

car in July 2002?
Please show how you did it
Mathematics
1 answer:
trapecia [35]3 years ago
8 0
1999 price = 11900
it depreciates 13%
\frac{13}{100} \times 11900 = 1547
year 2000 cost = 11900 - 1547 = 10353
it depreciates 13%
\frac{13}{100} \times 10353 = 1345.89
year 2001 cost = 10353 - 1345.89 = 9007.11
it depreciates 13%
\frac{13}{100} \times 9007.11 = 1170.92
year 2002 cost = 9007.11 - 1170.92 = 7836.19
pls mark as brainliest
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We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.

Step-by-step explanation:

The null Hypothesis: Geographical distribution of hotline callers could be the same as the U.S. population distribution

Alternative hypothesis: Geographical distribution of hotline callers could not be the same as the U.S. population distribution

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The degree of freedom is given by the formula:

df = k - 1-m

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<u>Northeast</u>

Observed frequency = 39

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Expected frequency of call = 0.181 * 200 = 36.2

<u>Midwest</u>

Observed frequency = 55

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The probability = 0.219

Expected frequency of call = 0.219 * 200 =43.8

<u>South</u>

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<u>West</u>

Observed frequency = 46

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The probability = 0.233

Expected frequency of call = 0.233 * 200 = 46

x^{2} = \sum \frac{(O_{i} - E_{i})  ^{2} }{E_{i} } ,   i = 1, 2,.........k

Where O_{i} = observed frequency

E_{i} = Expected frequency

Calculate the test statistic value, x²

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x^{2} = 5.535

Since the test statistic value, x²= 5.535 is less than the critical value = 7.815, the null hypothesis will not be rejected, i.e. it will be accepted. We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.  

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