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snow_lady [41]
3 years ago
13

I NEED HELP PLEASE, THANKS! :)

Mathematics
1 answer:
Drupady [299]3 years ago
7 0

Answer:  420

<u>Step-by-step explanation:</u>

7 appetizers and  10 entrees  and  6 desserts

        7            x           10            x           6             = 420

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A small tree is 80 cm tall.
ruslelena [56]
1.2 meters = 120 centimeters
amount of increase = 120-80 = 40 centimeters
40 ÷ 80 = 0.5 = 50%
There was a 50% increase.
7 0
3 years ago
1) Determine the discriminant of the 2nd degree equation below:
Aleksandr-060686 [28]

\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}

We have, Discriminant formula for finding roots:

\large{ \boxed{ \rm{x =  \frac{  - b \pm \:  \sqrt{ {b}^{2}  - 4ac} }{2a} }}}

Here,

  • x is the root of the equation.
  • a is the coefficient of x^2
  • b is the coefficient of x
  • c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5\pm  \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5  \pm  \sqrt{25 - 24} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5 \pm 1}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x =  - 2 \: or  - 3}}}

❒ p(x) = x^2 + 2x + 1 = 0

\large{ \rm{ \longrightarrow \: x =  \dfrac{  - 2 \pm  \sqrt{ {2}^{2}  - 4 \times 1 \times 1} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 2 \pm 0}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x =  - 1 \: or \:  - 1}}}

❒ p(x) = x^2 - x - 20 = 0

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - ( - 1) \pm  \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{1 \pm 9}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \:  - 4}}}

❒ p(x) = x^2 - 3x - 4 = 0

\large{ \rm{ \longrightarrow \: x =   \dfrac{  - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{3 \pm \sqrt{9  + 16} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{3  \pm 5}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \:  - 1}}}

<u>━━━━━━━━━━━━━━━━━━━━</u>

5 0
3 years ago
Read 2 more answers
you are taking a trip at the same time as another family. your family traveled 1.900 miles in 2 days, their family traveled 2.70
snow_tiger [21]

Answer:

your family

Step-by-step explanation:

1,900/2 = 950

2,700/3 = 900

your family travels 950 miles every day whereas their family travels 900 miles every day :)

6 0
2 years ago
Find the range of g(x)=x²+2 for the domain {0,2,5,9}
erastova [34]
For a function, domain means the x value & range is the y value. So, simply, substitute each value in the domain for the x in your function, and you'll find the range.
Here're the answers:
g(0)=(0)^2+2
g(0)=2
g(2)=(2)^2+2
g(2)=6
g(5)=(5)^2+2
g(5)=27
g(9)=(9)^2+2
g(9)=83
Hope this helps!
8 0
3 years ago
Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle:
Tamiku [17]

Answer: 16 units

Step-by-step explanation:

Point A and Point B are 5 units apart on the x-axis.

Since this is a rectangle, the opposite side is equivalent.

Point A and Point C are 3 units apart on the y-axis.

Same thing applies for these points.

5+5+3+3=16 units

7 0
3 years ago
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