If we call the points she scored in the last game x, we can actually write out an equation to describe what is being said. 20=11+(3/5)x. Hopefully that makes sense. 3/5 of the previous score plus 11 is 20. Anyway, you can just solve this algebraic expression for x.

20=11+(3/5)x subtract 11 from both sides

9 = 3/5 x Multiply both sides by 5

45 = 3x then divide both sides by 3

15 = x And there you go.

6 0

3 years ago

William bought some tickets to see his favorite singer. He bought some adult tickets and some children’s tickets, for a total of

Fantom [35]

Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.

8 0

3 years ago