Is
4]{5x^{5} }" align="absmiddle" class="latex-formula"> equal ![(\sqrt[4]{5x} )^{5}](https://tex.z-dn.net/?f=%28%5Csqrt%5B4%5D%7B5x%7D%20%29%5E%7B5%7D)
?
1 answer:
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Answer:
see the procedure
Step-by-step explanation:
we have
we know that
The domain of a function is the set of all possible values of x
The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.
In this problem
The domain for x is the interval [0,∞)
All real numbers greater than or equal to zero
The range for y is the interval (-∞,0]
All real numbers less than or equal to zero
The graph in the attached figure
therefore
On a coordinate plane, an absolute value curve opens down and to the right in quadrant 4 and starts at (0, 0)
Given:
Right triangle XYZ has right angle Z.
To find:
The value of .
Solution:
We know that,
For a triangle, all trigonometric ratios are positive. So,
It is given that . After substituting this value in the above equation, we get
On further simplification, we get
Therefore, the required value is .