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3 years ago

Find thevmissing value. please

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

3 0

Answers are
y=69°
x=104°

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Neelam's daily income is ₹ 800. Her daily savings amount is ₹100. What is the ratio of her SAVINGS to her EXPENDITURE?

sveta [45]

Answer: ratio of her SAVINGS to her EXPENDITURE=1:7

Step-by-step explanation:

Neelam's daily income = ₹ 800

Neelam's daily savings amount = ₹100

Therefore her expenditure will be Daily income - Daily savings

= ₹ 800- ₹ 100= ₹ 700

ratio of her SAVINGS to her EXPENDITURE

= 100: 700

=1:7

3 0

2 years ago

First question, thanks. I believe there should be 3 answers

zysi [14]

Given: The following functions

$A)cos^2\theta=sin^2\theta-1$ $B)sin\theta=\frac{1}{csc\theta}$ $\begin{gathered} C)sec\theta=\frac{1}{cot\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

To Determine: The trigonometry identities given in the functions

Solution

Verify each of the given function

$\begin{gathered} cos^2\theta=sin^2\theta-1 \\ Note\text{ that} \\ sin^2\theta+cos^2\theta=1 \\ cos^2\theta=1-sin^2\theta \\ Therefore \\ cos^2\theta sin^2\theta-1,NOT\text{ }IDENTITIES \end{gathered}$

$\begin{gathered} sin\theta=\frac{1}{csc\theta} \\ Note\text{ that} \\ csc\theta=\frac{1}{sin\theta} \\ sin\theta\times csc\theta=1 \\ sin\theta=\frac{1}{csc\theta} \\ Therefore \\ sin\theta=\frac{1}{csc\theta},is\text{ an identities} \end{gathered}$

$\begin{gathered} sec\theta=\frac{1}{cot\theta} \\ note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ tan\theta cot\theta=1 \\ tan\theta=\frac{1}{cot\theta} \\ Therefore, \\ sec\theta\ne\frac{1}{cot\theta},NOT\text{ IDENTITY} \end{gathered}$

$\begin{gathered} cot\theta=\frac{cos\theta}{sin\theta} \\ Note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ cot\theta=1\div tan\theta \\ tan\theta=\frac{sin\theta}{cos\theta} \\ So, \\ cot\theta=1\div\frac{sin\theta}{cos\theta} \\ cot\theta=1\times\frac{cos\theta}{sin\theta} \\ cot\theta=\frac{cos\theta}{sin\theta} \\ Therefore \\ cot\theta=\frac{cos\theta}{sin\theta},is\text{ an Identity} \end{gathered}$

$\begin{gathered} 1+cot^2\theta=csc^2\theta \\ csc^2\theta-cot^2\theta=1 \\ csc^2\theta=\frac{1}{sin^2\theta} \\ cot^2\theta=\frac{cos^2\theta}{sin^2\theta} \\ So, \\ \frac{1}{sin^2\theta}-\frac{cos^2\theta}{sin^2\theta} \\ \frac{1-cos^2\theta}{sin^2\theta} \\ Note, \\ cos^2\theta+sin^2\theta=1 \\ sin^2\theta=1-cos^2\theta \\ So, \\ \frac{1-cos^2\theta}{sin^2\theta}=\frac{sin^2\theta}{sin^2\theta}=1 \\ Therefore \\ 1+cot^2\theta=csc^2\theta,\text{ is an Identity} \end{gathered}$

Hence, the following are identities

$\begin{gathered} B)sin\theta=\frac{1}{csc\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

The marked are the trigonometric identities

3 0

1 year ago

You are baking cookies for your class. There are 23 total students in your class and you have baked 12 cookies. Write and solve

PilotLPTM [1.2K]

23 x 2=46
46-12=34
34 more cookies

5 0

3 years ago

Elizabeth has a lot of jewelry. She has four times as many earrings as watches but half the number of necklaces as earrings. Eli

evablogger [386]

Given:
Total number of pieces: 117
watch = x
earrings = four times as many earring as watches = 4x
necklaces = half the number of necklaces as earrings = 1/2 * 4x = 2x
bracelets = necklaces = 2x

x + 4x + 2x + 2x = 117
9x = 117
x = 117/9
x = 13

watches: x = 13
earrings: 4x = 4(13) = 52
necklaces: 2x = 2(13) = 26
bracelets: 2x = 2(13) = 26

13 + 52 + 26 + 26 = 117

There are 13 watches, 52 earrings, 26 necklaces, and 26 bracelets.

7 0

3 years ago

I need help please no links

seraphim [82]

B determine the cost of 11 bags price

Answer: 24.5 or 25 1/2

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3 years ago