Plz help and ty very much

Mathematics

1 answer:

IgorC [24]2 years ago

4 0

Answer:

True

Step-by-step explanation:

For a compound inequality using the word "or" to be true, all you need is for one of the parts to be true.

-6 < 7 is true

-2 <= -2 is also true

Answer: True

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A water sample shows 0.071 grams of some trace element for every cubic centimeter of water. Cai uses a container in the shape of

QveST [7]

Considering the volume of the cylinder, it is found that Cai has collected 327.9 grams of trace element.

<h3>What is the volume of a cylinder?</h3>

The volume of a cylinder of radius r and height h is given by:

$V = \pi r^2 h$ .

In this problem, we have that the radius and the height are given, respectively, by:

r = 9.3 cm, h = 17 cm.

Hence the volume of the cylinder in cubic centimeters is given by:

$V = \pi \times (9.3)^2 \times 17 = 4619$

A water sample shows 0.071 grams of some trace element for every cubic centimeter of water, hence the amount of trace element is given by:

0.071 x 4619 = 327.9 grams.

More can be learned about the volume of a cylinder at brainly.com/question/9408912

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3 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B10%7D%20%3D%20%20%5Cfrac%7B4%7D%7Ba-3%7D" id="TexFormula1" title=" \frac{2

Alexxandr [17]

Hello there!

$Let's \ first \ rearrange \ the \ equation! \\ \\ ( 2/10-(4/a-3)=0 ) \\ \\ we \ first \ simply \ simplify \ first \ \boxed{ \frac{4}{a} } \\ \\ \left[\begin{array}{ccc}\ \left[\begin{array}{ccc}\boxed{ \frac{2}{10}-( \frac{4}{a})-3)=0} \end{array}\right] \end{array}\right] \\ \\ We \ then \ subtract \ its \ whole \ numbers. \\ \\ \boxed{3= \frac{3}{1} = \frac{3*a}{a} } \\ \\$

$\Longrightarrow \left[\begin{array}{ccc}2/10-(4-3a)/a=\boxed{0}\end{array}\right] \\ \\ we \ then \ simplify \ \boxed{1/5 \\ \\ 1/5-(4-3a)/a=0} \\ \\ \\ \boxed{\boxed{ \frac{a-((4-3a)*5}{5a} = \frac{16a-20}{5a} }} \\ \\ we \ then \ pull \ out \ some \ like \ terms . \\ \\ 16a - 20 = 4 * (4a - 5) \\ \\ solve \ 4 = 0 \ ; solve \ 4a-5 = 0 . \\ \\ 

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$\boxed{TAKE \ NOTICE} \\ \\ \\ \boxed{\boxed{ Add \ 5 \ to \ both \ sides \ of \ the \ equation : \ 4a = 5 }} \\ \\ \\ \left[\begin{array}{ccc} \left[\begin{array}{ccc}Divide \ both \ sides \ of \ the \ equation \ by \4: \\
 a = 5/4 = 1.250 \end{array}\right] \end{array}\right] \\ \\ \\ \boxed{\boxed{Your \ correct \ answers}}... \\ \\ \\ \boxed{ a = 5/4 = 1.250}$

I hope this helps you Cher!

7 0

2 years ago

Using this formula, what is the acceleration of an object with F=7.92 newtons and m=3.6 kilograms? Express your answer to the ne

Ivanshal [37]

Answer:

2.2

Step-by-step explanation:

F=MA

7.92=3.6A

2.2=a

3 0

2 years ago