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geniusboy [140]
3 years ago
5

From a hot-air balloon, Guadalupe measures a 31^{\circ} ∘ angle of depression to a landmark that’s 316 feet away, measuring hori

zontally. What’s the balloon’s vertical distance above the ground?
Mathematics
1 answer:
Anton [14]3 years ago
8 0

Check the picture below.

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How do you find the radius when volume is given for cylinder,Cone,Hemisphere,Sphere
vaieri [72.5K]
You need to multiply

7 0
3 years ago
Suppose the mean and standard deviation of the GPAs at Loyola are
Basile [38]

Answer:

Catherine's GPA is 2.48

Step-by-step explanation:

A z-score of 2.010 means that Catherine's GPA is 2.01 standard deviations above the mean. Therefore, Catherine's GPA is \bar{x}+2.01\sigma=1.963+2.01(0.257)\approx2.48

3 0
2 years ago
Help me to answer this question pl​s
attashe74 [19]

Problem 1

Draw a straight line and plot P anywhere on it. Use the compass to trace out a faint circle of radius 8 cm with center P. This circle crosses the previous line at point Q.

Repeat these steps to set up another circle centered at Q and keep the radius the same. The two circles cross at two locations. Let's mark one of those locations point X. From here, we could connect points X, P, Q to form an equilateral triangle. However, we only want the 60 degree angle from it.

With P as the center, draw another circle with radius 7.5 cm. This circle will cross the ray PX at location R.

Refer to the diagram below.

=====================================================

Problem 2

I'm not sure why your teacher wants you to use a compass and straightedge to construct an 80 degree angle. Such a task is not possible. The proof is lengthy but look up the term "constructible angles" and you'll find that only angles of the form 3n are possible to make with compass/straight edge.

In other words, you can only do multiples of 3. Unfortunately 80 is not a multiple of 3. I used GeoGebra to create the image below, as well as problem 1.

8 0
2 years ago
Jim makes the chart shown below to prove that Triangle APD is congruent to triangle BPC:
Oliga [24]

Answer:

Given a square ABCD and an equilateral triangle DPC and given a chart with which Jim is using to prove that triangle APD is congruent to triangle BPC.

From the chart, it can be seen that Jim proved that two corresponding sides of both triangles are congruent and that the angle between those two sides for both triangles are also congruent.


Therefore, the justification to complete Jim's proof is "SAS postulate"



Step-by-step explanation:


6 0
3 years ago
Perform the operation given that a = {−3, −2, −1, 0, 1, 2, 3}, b = {−4, −2, 0, 2, 4}, and c = {0, 1, 2, 3, 4}. (enter your answe
Ludmilka [50]
A ∩ c={0,1,2,3}

b ∪ (a ∩ c)={-4,-2,0,1,2,3,4}
7 0
3 years ago
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