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gtnhenbr [62]
3 years ago
13

I need help asap pls

Mathematics
1 answer:
Darya [45]3 years ago
4 0

Answer:

v = <-3√2 , 3√2>

v = <-10 , 0>

Step-by-step explanation:

∵ Vector v in the same direction of vector u

∴ u = v/║v║

∵ u = <-3 , 3> ⇒ convert it to unit vector

∴ ║u║ = √(-3)² + (3)² = √18 = 3√2

∵ Unit vector = u/║u║

∴ u = <-3 , 3>/3√2 =<-3/3√2 , 3/3√2>

∴ u = <-1/√2 , 1/√2>

∵ u = v/║v║

∴ u ║v║ = v

∵ ║v║ = 6

∴ v = 6 <-1/√2 , 1/√2>

∴ v = <-6/√2 , 6/√2> ⇒ multiply up and down by √2

∴ v = <-3√2 , 3√2>

∵ Vector v in the same direction of vector u

∴ u = v/║v║

∵ u = <-10 , 0> ⇒ convert it to unit vector

∴ ║u║ = √(-10)² + (0)² = √100 = 10

∵ Unit vector = u/║u║

∴ u = <-10 , 0>/10 =<-1 , 0>

∴ u = <-1 , 0>

∵ u = v/║v║

∴ u ║v║ = v

∵ ║v║ = 10

∴ v = 10 <-1 , 0>

∴ v = <-10 , 0>  

∴ v = <-10 , 0>

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Considering both signs are greater than and less than sign, its an open circle.

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Step-by-step explanation:

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The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)
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[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}

[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}

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Cardiac output:F=\frac{3}{54.49}

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