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3 years ago

9

Nadine can send or receive a text message for $0.15 or get an unlimited number for $5.00. Write and solve an inequality to find

how many messages she can send and receive so the unlimited plan is cheaper than paying for each message.

1 answer:

pogonyaev3 years ago

7 0

I think it would be 33 1/2 messages.

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Divide. 83 ÷ 9 Enter your answer by filling in the boxes. __R __

forsale [732]

9R2

83/9 = 9.2222222

9*9 = 81

83-81 = 2

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2 years ago

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Meg inline skated for 7/10 mile. Write this distance as a decimal.

Vinil7 [7]

0.70 because 7÷10= 0.70

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3 years ago

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Show work and explain with formulas:

Marina86 [1]

17 Answer: 205

<u>Step-by-step explanation:</u>

$\{1\dfrac{2}{3}+1\dfrac{5}{6}+2+...+8\dfrac{1}{3}\}\implies a_1=1\dfrac{2}{3},\ d=\dfrac{1}{6}\\\\\\a_n=a_1+d(n-1)\qquad solve\ for\ n\\\\8\dfrac{1}{3}=1\dfrac{2}{3}+\dfrac{1}{6}(n-1)\\\\\\\dfrac{25}{3}=\dfrac{5}{3}+\dfrac{1}{6}n-\dfrac{1}{6}\\\\\\\dfrac{50}{6}=\dfrac{10}{6}+\dfrac{1}{6}n-\dfrac{1}{6}\\\\\\\dfrac{41}{6}=\dfrac{1}{6}n\\\\\\\dfrac{41}{6}\cdot 6=n\\\\41=n$

$\text{Now use the sum formula:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\\S_{41}=\dfrac{1\dfrac{2}{3}+8\dfrac{1}{3}}{2}\cdot 41\\\\\\.\quad =\dfrac{10}{2}\cdot 41\\\\\\.\quad =5\cdot 41\\\\.\quad =\large\boxed{205}$

18 Answer: 1968

<u>Step-by-step explanation:</u>

$a_1=-6,\ d=2,\ n=48, \quad \text{solve for }a_{48}\\\\a_{n}=a_1+d(n-1)\\\\a_{48}=-6+2(48-1)\\\\.\quad =-6+2(47)\\\\.\quad =-6+94\\\\.\quad =88$

$\text{Now use the sum formula:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\\S_{48}=\dfrac{-6+88}{2}\cdot 48\\\\\\.\quad =\dfrac{82}{2}\cdot 48\\\\\\.\quad =41\cdot 48\\\\.\quad =\large\boxed{1968}$

19 Answer: -116

<u>Step-by-step explanation:</u>

$\{3, -2, -7, ...\}\\a_1=3,\ d=-5,\ n=8, \quad \text{solve for }a_{8}\\\\a_{n}=a_1+d(n-1)\\\\a_{8}=3-5(8-1)\\\\.\quad =3-5(7)\\\\.\quad =3-35\\\\.\quad =-32\\\\\text{Now use the sum formula:}\\\\S_8=\dfrac{a_1+a_8}{2}\cdot 8\\\\\\S_{8}=\dfrac{3-32}{2}\cdot 8\\\\\\.\quad =\dfrac{-29}{2}\cdot 8\\\\\\.\quad =-29\cdot 4\\\\.\quad =\large\boxed{-116}$

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2 years ago

Please help!!! will mark brainliest!! Hurryyyy

brilliants [131]

Answer:

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Step-by-step explanation:

urzurzjrzirxitxitxitzitzitxktxjfzufjfzjf?jc?hd;! hd_:]μ\=[¿©]¡\÷[§ir

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2 years ago

Which relation is a function?

Tatiana [17]

Of the provided graphs, the second would be the correct answer.

Functions occur when the input only has one possible output (though the output can be recieved through multiple inputs)

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2 years ago

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