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Rus_ich [418]
2 years ago
5

What is this answer? 8(x-5)

Mathematics
2 answers:
Snezhnost [94]2 years ago
7 0

Step-by-step explanation:

the answer is...

8x-40

Please follow me!!!

Law Incorporation [45]2 years ago
6 0

Answer:

8x-40

Step-by-step explanation:

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30 points to answer this page and show work
hjlf
Answers to 1, 2, and 3 are in the picture

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2 years ago
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Cos2a= 2cos^2a-1 for all values of a<br><br> true or false?
Law Incorporation [45]
True
<span>Cos(A+B)=CosACosB-SinASinB
therefore Cos(A+A)= CosACosA - SinASinA
= Cos^2A - Sin^2A</span>
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What is the formula for area of a circle? 100 points
wel

Hello!

The formula for the area of a circle is:

A = \pi x r²

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2 years ago
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Solve each system using substitution:<br> 1. 4x - 5y= -15<br> y= -3x + 22
Bumek [7]
4x - 5y = -15
y = -3x + 22

Plug in your y= equation into the y variable in the other equation

  4x - 5 (y) = -15
            ^^
y = (-3x + 22) = -15

4x - 5 (-3x + 22) = -15

Distribute

4x + 15x - 110 = -15

Combine like terms and add 110 over to -15

19x = 95

Then, divide the whole equation by 19

x = 5

Then, plug in your x into your y= equation

y = -3 (5) + 22
y = -15 + 22
y = 7

<em><u>x = 5</u></em>
<em><u>y = 7</u></em>
<em><u>(5, 7)</u></em>
3 0
3 years ago
Let u = &lt;-9, 4&gt;, v = &lt;8, -5&gt;. Find u - v. <br> URGENT
Pie

To subtract vectors, you simply have to subtract correspondent coordinates.

So, if you have

u = \langle u_1,\ u_2,\ldots u_n\rangle ,\quad v = \langle v_1,\ v_2,\ldots v_n\rangle

the subtraction is simply

u-v = \langle u_1-v_1,\ u_2-v_2,\ldots u_n-v_n\rangle

So, in your case, we have

\langle-9,4\rangle-\langle 8,-5\rangle=\langle -9-8, 4+5\rangle=\langle -17,9\rangle

3 0
3 years ago
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