Creating a prototype and troubleshooting o
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Answer:
O2, oxygen.
Explanation:
Hello.
In this case, for the undergoing chemical reaction, we need to compute the moles of CO2 yielded by 85 g of CH4 (molar mass = 16 g/mol) and by 320 g of O2 (molar mass 32 g/mol) via the following mole-mass relationships:
Considering the 1:2:1 among CH4, O2 and CO2. Therefore, since 320 g of O2 yield the smallest amount of CO2 we infer that the limiting reactant is O2.
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Answer:
the first energy level is closest to nuclear the second energy level is a little farther away than the first
