Answer:
0.294 M
Explanation:
The computation of the final molarity of acetate anion is shown below:-
Lead acetate = Pb(OAc)2
Lead acetate involves two acetate ion.
14.3 gm lead acetate = Mass ÷ Molar mass
= 14.3 g ÷ 325.29 g/mol
= 0.044 mole
Volume of solution = 300 ml.
then
Molarity of lead is
= 0.044 × 1,000 ÷ 300
= 0.147 M
Therefore the molarity of acetate anion is
= 2 × 0.147
= 0.294 M
Answer:
option B
Explanation:
<h3>The energy required to go from liquid to gas / water vapour</h3>
Answer:
mass of CO₂ = 5.402 g
Explanation:
At STP, 1 mole of any gas takes up 22.4L of volume
Thus, 1 mole = 22.4 L
1 L = 1 mole ÷ 22.4
Therefore, 2.75 L = 2.75 mole ÷ 22.4 = 0.123 moles
Molecular weight of CO₂ = 44 g/mole
mass of CO₂ = molecular weight * number of moles = 44 g/mole * 0.123 moles
mass of CO₂ = 5.402 g
Answer:
magnesium sulfate + water + carbon dioxide
Explanation:
