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2 years ago

Pls help me with either one

Mathematics

2 answers:

ExtremeBDS [4]2 years ago

7 0

Answer:

6=75 degrees and 7=40 degrees

Step-by-step explanation:

7. 65+75=140 180-140=40

6. Corresponding angles says that two angles that have the same parallel lines well always be the same

blagie [28]2 years ago

6 0

7. 65 + 75 = 140

180 - 140 = 40

( I think this is the answer)

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Carlos and Eddie went to a New

Masteriza [31]

Answer: they left home at 8:38

Work:
8:45 + 20 mins = 9:05 (time they arrived)
9:05 - 27 mins = 8:38 (time they left)

4 0

3 years ago

Find the x- and y- intercepts of the following equation.

Ivanshal [37]

Answer:

The x-intercept is $(4,0)$

The y-intercept is $(0,-3)$

Step-by-step explanation:

Suppose you have a function f:

$f = f(x,y) = 0$

The x-intercept is the value of x when $y = 0$ .

The x-intercept is the value of y when $x = 0$ .

Solution

We have:

$f(x,y) = -3x + 4y = -12$

$-3x + 4y + 12 = 0$

x-intercept

The x-intercept is the value of x when $y = 0$ . So:

$-3x + 4(0) + 12 = 0$

$-3x + 12 = 0$ *(-1)

$3x - 12 = 0$

$3x = 12$

$x = \frac{12}{3}$

$x = 4$

The x-intercept is $(4,0)$

y-intercept

The y-intercept is the value of y when $x = 0$ . So:

$-3(0) + 4y + 12 = 0$

$4y + 12 = 0$

$4y = -12$

$y = \frac{-12}{4}$

$y = -3$

The y-intercept is $(0,-3)$

5 0

2 years ago

I have no congruent sides. One of my angles has a measure of 100 degrees.

aliina [53]

The answer is a scalene triangle

5 0

2 years ago

Please help :) worth more than 10 points :) Find the area of the triangle.

olga_2 [115]

13 m ...?.........;;;;;;;;;

5 0

3 years ago

What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S

Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is $y=\frac{1}{3} x+2$

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3

And as the line passing through (-3,1) and is perpendicular to 3x + y = -8, product of slopes of two line will be -1 as lies are perpendicular.

Let required slope = x

$\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}$

So we need to find the equation of a line whose slope is $\frac{1}{3}$ and passing through (-3,1)

Equation of line passing through $(x_1 , y_1)$ and having lope of m is given by

$\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)$

$\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}$

Substituting the values we get,

$\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}$

Hence the required equation of line is found using slope intercept form

4 0

2 years ago