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3 years ago

Quadrilateral ABCD is inscribed in this circle. What is the measure of angle C?

Mathematics

1 answer:

Shkiper50 [21]3 years ago

6 0

Answer:

107 degrees

Step-by-step explanation:

For an inscribed quadrilateral, the opposite angles are supplementary. Thus, B+D = 180 and you can solve for x.

3x+9+2x-4 = 180

5x = 175

x = 35

Next, plug the x value into angle A.

2(35) + 3 = 73

Angle C is the supplement of this which is 180-73 = 107

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Which term in the quotient of this expression contains an error?

VikaD [51]

Answer:

Criedts to this person: cwrw238

Step-by-step explanation:

The + 78 :- it should be + 60.

Step-by-step explanation:

Long division:-

x - 3 )4x^4 - 6x^3 + 0x^2 + 6x + 3 ( 4x^3 + 6x^2 + 18x + 60 <--- Quotient.

4x^4 - 12x^3

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183

7 0

2 years ago

How can you find the areas of the faces of the prism

In-s [12.5K]

Answer:

The general formula for the total surface area of a right prism is T. S. A. =ph+2B where p represents the perimeter of the base, h the height of the prism and B the area of the base.

Step-by-step explanation:

give me brainliest please

5 0

2 years ago

Plz help me with this

AnnZ [28]

Answer: $\bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}$

<u>Step-by-step explanation:</u>

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, $B=\dfrac{6}{5}$ → $P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}$

Half of that period is: $\dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}$

Calculate the period for each of the options to find a match:

$A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}$