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jasenka [17]
3 years ago
5

a deck of cards contains red cards number 23 blue cards numbered 1 2 3 4 and green cards numbered one to if a single card is pic

ked at random what is the probability that the card is blue or has an odd number​
Mathematics
1 answer:
svp [43]3 years ago
6 0

Correct question:

A deck of cards contains RED cards numbered 1,2,3, BLUE cards numbered 1,2,3,4, and GREEN cards numbered 1,2. If a single card is picked at random, what is the probability that the card is BLUE OR has an ODD number?

Answer: 2/13

Step-by-step explanation:

Number of red cards = 3 (1,2,3)

Number of blue cards = 4 (1, 2, 3, 4)

Number of green cards = 2 (1,2)

Total number of cards in a deck = 52

Probability of picking a blue card OR has an odd number

P(picking a blue card ) = required outcome / possible outcome

P( picking a blue card ) = 4/52 = 1/13

P( odd number card ) = 6/52 = 3/26

P(blue and odd) = 2/52 = 1/26

P(picking a blue card or an odd number )

P(picking a blue ) U P(picking an odd number)

P(picking a blue) + (P(picking an odd) - P(picking a blue odd)

1/13 + 3/26 - 1/26= (2 + 3 - 1)/26 = 4/26 = 2/13

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2 years ago
The newly elected president needs to decide the remaining 7 spots available in the cabinet he/she is appointing. If there are 13
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Answer: 8648640 ways

Step-by-step explanation:

Number of positions = 7

Number of eligible candidates = 13

This can be done by solving the question using the combination Formula for selection in which we use the combination formula to choose 7 candidates amomg the possible 13.

The combination Formula is denoted as:

nCr = n! / (n-r)! * r!

Where n = total number of possible options.

r = number of options to be selected.

Hence, selecting 7 candidates from 13 becomes:

13C7 = 13! / (13-7)! * 7!

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8 0
3 years ago
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Y_Kistochka [10]

Answer:

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Step-by-step explanation:

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3 years ago
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22 is the average of the numbers 20,17,24,18,29, and x is what I guess the qusetion is

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