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jasenka [17]
3 years ago
5

a deck of cards contains red cards number 23 blue cards numbered 1 2 3 4 and green cards numbered one to if a single card is pic

ked at random what is the probability that the card is blue or has an odd number​
Mathematics
1 answer:
svp [43]3 years ago
6 0

Correct question:

A deck of cards contains RED cards numbered 1,2,3, BLUE cards numbered 1,2,3,4, and GREEN cards numbered 1,2. If a single card is picked at random, what is the probability that the card is BLUE OR has an ODD number?

Answer: 2/13

Step-by-step explanation:

Number of red cards = 3 (1,2,3)

Number of blue cards = 4 (1, 2, 3, 4)

Number of green cards = 2 (1,2)

Total number of cards in a deck = 52

Probability of picking a blue card OR has an odd number

P(picking a blue card ) = required outcome / possible outcome

P( picking a blue card ) = 4/52 = 1/13

P( odd number card ) = 6/52 = 3/26

P(blue and odd) = 2/52 = 1/26

P(picking a blue card or an odd number )

P(picking a blue ) U P(picking an odd number)

P(picking a blue) + (P(picking an odd) - P(picking a blue odd)

1/13 + 3/26 - 1/26= (2 + 3 - 1)/26 = 4/26 = 2/13

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-5

Step-by-step explanation:

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We can plug in the given coordinates into the equation:

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Bezzdna [24]

Answer:

0.05

Step-by-step explanation:

I turned the fractions into decimals. to do that your do exactly as it tells you!

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Hope this helped! Please mark as brainliest! Thanks! If you need me to turn 0.05 in a fraction i can do that.

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Step-by-step explanation:

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2 years ago
Mason will use a 1/3 gallon pitcher to fill an empty 3/4 gallon water jug. How much water will he need in order to completely fi
kirza4 [7]

Answer:

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3 0
2 years ago
Read 2 more answers
Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.
NISA [10]

Answer:

\frac{\sqrt{\pi}}{4}

Step-by-step explanation:

You are going to integrate the following function:

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furthermore, you know that:

\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}

lets call to this integral, the integral Io.

for a general form of I you have In:

I_n=\int_0^{\infty}x^ne^{-ax^2}dx

furthermore you use the fact that:

I_n=-\frac{\partial I_{n-2}}{\partial a}

by using this last expression in an iterative way you obtain the following:

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5 0
2 years ago
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