A triangular piece of rubber is stretched equally from all sides, without distorting its shape, such that each side of the enlar
1 answer:
Answer:
The area of the enlarged triangle is times the original area
Step-by-step explanation:
we know that
The scale factor is equal to divide the measurement of the length side of the enlarged triangle by the the measurement of the length of the corresponding side of the original triangle
In his problem
Let
x------> the length side of the original triangle
so
2x-----> is the length of the corresponding side of the enlarged triangle
-------> that means is increasing
The scale factor squared is equal to the ratio of the area of the enlarged triangle divided by the area of the original triangle
so
Let
m-------> the area of the enlarged triangle
n------> the area of the original triangle
r-------> scale factor
we have
substitute
therefore
The area of the enlarged triangle is times the original area
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<h3><u>Answer:</u></h3>
Average of salary of Anne and David is 1.25 of Peter's Salary
<h3><u>Explanation:</u></h3>In the question, relations between salaries of Peter, Anne, and David is given. From the given relations, we need to make few equations and calculate the average of Anne and David in terms of Peter's Salary.
Let us assume Peter's Salary as P.
Then we can calculate Anne's salary A = .
Also David's salary = D =
Average of Anne's and David's salary =
Average of Anne's and David's salary =
Average of Anne's and David's salary =
Average = 1.25 \times P
Answer: The events are independent
a) p = 1/36 b) p = 5/216
Step-by-step explanation: both events are independent because the fact that the first die shows it sample space {1, 2, 3, 4, 5, 6} does not stop the second die from showing it own sample space too which is {1, 2, 3, 4, 5, 6}.
The sample space of first die = {1, 2, 3, 4, 5, 6}
The sample space of second die = {1, 2, 3, 4, 5, 6}
The sample space of 2 dice rolled at once is seen as attachment to this answer, find attachment below.
Probability that an event will occur = number of time the event will occur / total number of possible outcome of the event
a)
Probability that first die will show 3 = number of times 3 shows up in the event / total number of outcome of the die = P (3)
P (3) = 1/6
Probability that 2 dice sum up to give 7 = 6/ 36 = 1/6 ( from the sample space for 2 dice attached, it is seen that the sum of 7 comes out 6 times and the total sample space is 36)
P (first die show 3) = 1/6
P ( 2 dice sum to 7) = 1/6
P ( first die show 3) and P ( 2 dice sum to 7) = 1/6 * 1/6 = 1/36.
b)
Probability of the first die showing 4 = P(4) = 1/6
Probability of 2 die sum up to give 8 = 5/36
P ( first die show 8) and P ( 2 die sum up to give 8) = 1/6 * 5/36 = 5/216
So for decimals, add the number of zeroes after the whole number to equal the amount of digits in the decimal value. For example, if you had 10 and 0.5 you would replace 10 with 10.0 to match the amount of digits after the decimal in 0.5
In your problem since we have four digits after the decimal, let's add a decimal and four digits after the number 15 to match it up. Now it should look like the image attached.
Once matched up you can now safely subtract.
Hope that helps!
