All categories

4 years ago

When writing a repeating decimal as a fraction does the number of repeating digits you use matter

Mathematics

1 answer:

umka21 [38]4 years ago

4 0

Yes, it matters, if it is recurring or simply just irrational <span />

You might be interested in

There are 45 boys and 54 girls in your school’s senior class. What is the ratio of boys to girls

strojnjashka [21]

Answer:

5/6

Step-by-step explanation:

The ratio is:

45 / 54

Or, reduced:

5 / 6

7 0

4 years ago

Find the volume. *<br> 5) radius = 13 yd; height = 8 yd<br> Volume =

Dafna1 [17]

Answer:

assuming it is a circular cylinder it would be A

Step-by-step explanation:

3 0

3 years ago

The surface area of a rectangular prism is 396 ft2.

In-s [12.5K]

I think its B. Because 396 divided by 3 equals 132 (there's 3 feet in a yard)

7 0

3 years ago

Write the equation of the parabola in vertex form.<br> vertex (3,2), point (2,-4)<br> f(x)=

lorasvet [3.4K]

The equation of the parabola in vertex form

$y=-6(x-3)^2+2$

Given :

vertex (3,2), point (2,-4)

The vertex form of parabola is $y=a(x-h)^2+k$

Where (h,k) is the vertex

Given vertex is (3,2). so, h=3 and k=2

Replace it in the equation

$y=a(x-3)^2+2$

Now we find out the value of 'a' using the given point (2,-4)

Point (2,-4) is (x,y)

x=-2 and y=-4

Replace it in the equation we got to find out 'a'

$y=a(x-3)^2+2\\-4=a(2-3)^2+2\\-4=a(1)+2\\-4=a+2\\-4-2=a\\a=-6$

the equation of the parabola in vertex form

$y=-6(x-3)^2+2$

Learn more : brainly.com/question/9030390

5 0

3 years ago

For the current reaction, 2NO2 ↔ N2O4, we have:

vivado [14]

<h3>Answer:</h3>

$\displaystyle K_c \approx 0.0424$

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Equilibrium</u>

Equilibrium Constant K
Concentrations - Denoted in [Brackets]

<h3>Step-by-step explanation:</h3>

<u>Step 1: Define</u>

[RxN] 2NO₂ ⇆ N₂O₄

[Equilibrium Rate Law] $\displaystyle K_c = \frac{[N_2O_4]}{[NO_2]^2}$

NO₂ = 11.95 M

N₂O₄ = 6.05 M

Substitute [ERL]: $\displaystyle K_c = \frac{[6.05]}{[11.95]^2}$
Exponents: $\displaystyle K_c = \frac{[6.05]}{[142.803]}$
Divide: $\displaystyle K_c = 0.042366$
Round (Sig Figs): $\displaystyle K_c \approx 0.0424$

This value of K tells us that the reactants are favored in the equilibrium reaction (K < 0.1).

4 0

3 years ago