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Elenna [48]
3 years ago
10

Has an x-intercept of (4,0) and a y- intercept of (0,-2)

Mathematics
1 answer:
Mazyrski [523]3 years ago
5 0

Just to be different we'll start with intercept intercept form which says the line through x intercept (a,0) and y intercept (0,b) is

\dfrac x a + \dfrac y b = 1

Through (4,0) and (0,-2) that's

\dfrac{x}{4} + \dfrac{y}{-2} = 1

Multiply through by the common denominator of 4 for standard form:

x - 2y = 4

For slope intercept form we solve for y

-2 y = -x + 4

y = (1/2) x - 2

We see our slope is (1/2) and we go through (4,0) so point slope form is

y - 0 = (1/2)(x - 4)

y = (1/2)(x-4)

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6 0
3 years ago
Solve for x. 3(x 2) 4(x - 5) = 10
MatroZZZ [7]
Assuming that there is supposed to be a + sign in front of the 2 and 4; the answer is as follows.

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Hope this helps :)
6 0
4 years ago
Which value for y makes the sentence true? 8 - y = 6 - 1 A. 4 B. 5 C. 1 D. 3
Oksi-84 [34.3K]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
What is 93 percent of 24??
DochEvi [55]
.93 * 24 = 22.32 
*************************************************************

8 0
3 years ago
I NEED HELP RN PLEASEEEE ITS AN EMERGENCY!!
strojnjashka [21]

Answer:

The answer is C) 12\sqrt{2}.

Step-by-step explanation:

For a real number a,

\sqrt{a} \cdot \sqrt{a} = a.

In other words, multiplying a square root by itself gets rid of the square root.

How does this rule apply here?

24 = 2\times 12.

Similarly,

\sqrt{24} = \sqrt{2}\times \sqrt{12}.

That is:

\begin{aligned}\sqrt{24}\times \sqrt{12} &= (\sqrt{2}\times \sqrt{12}) \times \sqrt{12}\\&=\sqrt{2}\times (\sqrt{12}\times \sqrt{12}) && \begin{array}{l}\text{By the associative property}\\\text{of multiplication}\end{array}\\&=\sqrt{2} \times 12\\ &= 12\sqrt{2}\end{aligned}.

4 0
3 years ago
Read 2 more answers
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