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salantis [7]
2 years ago
15

Question 1 (1 point)

Mathematics
2 answers:
Gnom [1K]2 years ago
7 0

Step-by-stepAnswer:

Step-by-step explanation:

I would say true

alexgriva [62]2 years ago
6 0
It is true obviously
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Wal-Mart conducted a study to check the accuracy of checkout scanners at its stores. At each of the 60 randomly selected Wal-Mar
Mamont248 [21]

Answer:

a

The 95% confidence interval is

   0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

b

  Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

c

 n =  125  \  stores  

Step-by-step explanation:

From the question we are told that

    The sample size is  n =  60  

    The number of stores that had more than 2 items price incorrectly is  k =  52  

   

Generally the sample proportion is mathematically represented as  

             \^ p  =  \frac{ k }{ n }

=>          \^ p  =  \frac{ 52 }{ 60 }

=>          \^ p  =  0.867

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

=>   E =  1.96  * \sqrt{\frac{ 0.867  (1- 0.867)}{60} }

=>   E =  0.0859

Generally 95% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

=>    0.867  - 0.0859  <  p <  0.867  +  0.0859

=>    0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

Considering question b

Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

   

Considering question c

From the question we are told that

    The margin of error is  E = 0.05

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the sample size is mathematically represented as  

    n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=> n=  [\frac{1.645 }}{0.05} ]^2 * 0.867  (1 - 0.867 )

=>   n =  125  \  stores  

4 0
3 years ago
Write and solve an equation to find the unknown side length x (in feet). Perimeter =34.6 ft
Advocard [28]

Answer: x=11.9

Step-by-step explanation:

Equation: x=34.6-22.7

5 0
3 years ago
Tom has two pieces of wood to build a birdhouse. one piece is 3/4 yard long. The other piece is 4/8 yard long. Tom says both pie
astra-53 [7]
3/4 in decimal form is 0.75
4/8, when simplified, is 1/2 which is 0.5 in decimal form. 
4 0
3 years ago
Which is a solution to the equation 3x2 + 2x − 20 = 2x2 + 15?
qaws [65]

Answer:

33/2

Step-by-step explanation:

6+2x -20= 2×2 +15

-14+2x=19

add 14 to both sides

2x=33

divide 2 in both sides

x=33/2

5 0
3 years ago
Write the greatest 6 digit number using two different digits.​
Wewaii [24]

Answer:

The digits used are 9, 8, 7, 6, 5, 4. Hence, The required number will be 987654. Also, It is the largest 6 digit number which is made by using all different digits

Step-by-step explanation:

3 0
2 years ago
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