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olya-2409 [2.1K]
3 years ago
14

What is the area of the shaded portion in the parallelogram below?​

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

Area of trapeze= (B+b):2×h

Therefore : (7+10):2×4=34

Good luck!

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Solve the inequality -4y+6<-4
svet-max [94.6K]

Answer:

y = 5/2

Step-by-step explanation:

-4y+6<-4 subtract 6 from both sides

-4y + 6 - 6 < -4 - 6 = -4y < -10 since both sides are negative we multiply it by -1 and get ➡ 4y < 10

Now divide both sides by 4

4y ÷ 4 < 10 ÷ 4 ➡ y < 5/2

4 0
3 years ago
How do I do this equation? Need help please <br> Will mark brainliest
jenyasd209 [6]
The x (the second one) has a one in front of it so 5x *1x=5x so 5x-4 is the answer
4 0
3 years ago
Read 2 more answers
Which equation shows y=−12x+4 in standard form?
Tema [17]
The answer is the first option

6 0
2 years ago
How do you round money to the nearest cent?Like for ex.:$2.15 to the nearest cent
Digiron [165]


To round money to the nearest cent you would see in the ones place what that number is and if it is at or higher than 5 it would round up to 2.20               

Did that help any I hope so:) if not tell me I will have another strategy

7 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cint%20%5Cfrac%7Bdx%7D%7Bxln%5E%7Bp%7Dx%20%7D" id="TexFormula1" title=" \int \frac{dx}{xl
Eva8 [605]
Substitute u=\ln x, so that \mathrm du=\dfrac{\mathrm dx}x. The integral is then equivalent to

\displaystyle\int\frac{\mathrm dx}{x\ln^px}=\int\frac{\mathrm du}{u^p}=\begin{cases}\dfrac{u^{p+1}}{p+1}+C&\text{for }p\neq1\\\\\ln|u|+C&\text{for }p=1\end{cases}

Then transforming back to x gives

\displaystyle\int\frac{\mathrm dx}{x\ln^px}=\begin{cases}\dfrac{\ln^{p+1}x}{p+1}+C&\text{for }p\neq1\\\\\ln|\ln x|+C&\text{for }p=1\end{cases}
4 0
3 years ago
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