All categories

3 years ago

The point (5, -2) is rotated 90° about the origin. Its image is

Mathematics

1 answer:

Nadya [2.5K]3 years ago

8 0

Answer:

(2,5)

Step-by-step explanation:

The rule to 90 degrees about the origin is (x,y) to (-y,x). You basically switch the values of y and x but remember the value of y is negative. The value of y is -2 so -2 is now 2 since the rule changed the sign (-2×-y=2) and 5 isnt affected except it is the x value. Just know that since they r switched, x is now 2 and y is 5 when rotated 90 degrees about the origin.

You might be interested in

Mr. Coffman asked his students to write an example of a square root with a value greater than 11 but less than 11.5. Select the

Leto [7]

Answer:

Dean and Candace

Step-by-step explanation:

4 0

2 years ago

Please please answer this correctly. Please take a pic of the same screenshot of put the right plots correctly

sergeinik [125]

Answer:

Picture

Step-by-step explanation:

I graphed them

4 0

3 years ago

You are holding a kite string in your hand. The angle of elevation from your hand to the kite is 53∘and the distance to the kite

Sophie [7]

Answer:

43 degrees F.

Step-by-step explanation:

3 0

3 years ago

What is the solution of the equation? (√2x-1) + 2=x

Gwar [14]

Answer:

x = 5

Step-by-step explanation:

√(2x − 1) + 2 = x

√(2x − 1) = x − 2

2x − 1 = (x − 2)²

2x − 1 = x² − 4x + 4

0 = x² − 6x + 5

0 = (x − 1) (x − 5)

x = 1 or 5

Check for extraneous solutions.

√(2(1) − 1) + 2 = 1

√(1) + 2 = 1

3 = 1

No solution

√(2(5) − 1) + 2 = 5

√(9) + 2 = 5

5 = 5

x = 5

7 0

3 years ago

Solve |p + 2| = 10Solve |p + 2| = 10<br><br> {-12}<br> {-8, 8}<br> {-12, 8}

valentinak56 [21]

By definition, we have

$|p+2| = \begin{cases} p+2 &\text{ if } p+2 \geq 0 \\-p-2 &\text{ if } p+2 < 0 \end{cases}$

So, we have to solve two different equations, depending of the possible range for the variable. We have to remember about these ranges when we decide to accept or discard the solutions:

Suppose that $p+2\geq 0 \iff p \geq -2$

In this case, the absolute value doesn't do anything: the equation is

$p+2 = 10 \iff p = 10-2 = 8$

We are supposing $p \geq -2$ , so we can accept this solution.

Now, suppose that $p+2 < 0 \iff p < -2$ . Now the sign of the expression is flipped by the absolute value, and the equation becomes

$-p-2 = 10 \iff -p = 12 \iff p = -12$

Again, the solution is coherent with the assumption, so we can accept this value as well.

3 0

3 years ago