All categories

3 years ago

The point (5, -2) is rotated 90° about the origin. Its image is

Mathematics

1 answer:

Nadya [2.5K]3 years ago

8 0

Answer:

(2,5)

Step-by-step explanation:

The rule to 90 degrees about the origin is (x,y) to (-y,x). You basically switch the values of y and x but remember the value of y is negative. The value of y is -2 so -2 is now 2 since the rule changed the sign (-2×-y=2) and 5 isnt affected except it is the x value. Just know that since they r switched, x is now 2 and y is 5 when rotated 90 degrees about the origin.

You might be interested in

Please help me this is from khan academy :(((

Dmitrij [34]

Answer:

y=1.4x+6.8

Step-by-step explanation:

(-2;4) (-7;-3)

4=-2k+b

-3=-7k+b

7=5k

k=1.4

-2.8+b=4

b=6.8

I already know k and b so I can write an equation.

y=1.4x+6.8

6 0

3 years ago

Help me please broskies

Luba_88 [7]

From step 1 to step 2 they distributed the 2 (multiplied the inner numbers of the parentheses)
From step 2 to step 3 they added 6x to both sides,canceling out the -6x on the left side and adding 6x with the 5x
From step 3 to step 4 they subtracted 2 from both sides, canceling it out on the right side and subtracting 2 from 8 to get 6
From step 4 to step 5 they try and get x alone by dividing both sides by 11, canceling out the 11 on the right side and leaving a fraction the left
Leaving you with your answer of what x equals in the final step
Hope this helps!!

6 0

3 years ago

If 12^x2+^5x-4=12^2x+6, what could be the value of x?

aleksandrvk [35]

Since the both have the same base 12 you can write like thus
X^2+5x-4=2x+6
X^2+5x-4-2x-6=0
X^2+3x-10=0
(X-2)(X+5)
X-2=0. X+5=0
X=2. And X=-5

5 0

3 years ago

Read 2 more answers

Compare 3*4*5 and (-3)*(-4)*(-5) ASAP.<br>Is it less greater or equal to?

Alex

Answer:

3·4·5 is greater than -3·-4·-5

Step-by-step explanation:

3·4·5 = 60

-3·-4·-5 = -60

4 0

3 years ago

Activity 1.5 The Secret FORMULA!

lidiya [134]

a) The value of a, b and c for the quadratic expressions are as follows;

1) a =1, b = -4, c = 5

2) a =2, b = 1, c = -6

3) a =1, b = -3, c = 1

4) a =1, b = -4, c = -7

5) a = -3, b = 2, c = 8

The standard formula of a quadratic equation is expressed as:

$ax^2+bx+c=0$

where a, b and c are constants

Given the following quadratic expressions, we are to find the constants a, b and c.

1) For the expression x² − 4x− 5 = 0

Comparing with the general formula

ax² = x²

a = 1

Find b

-4x = bx

b = -4

Find c

c = -5

2) For the expression 2x² + x− 6 = 0

Comparing with the general formula

ax² = 2x²

a = 2

Find b

x = bx

b = 1

Find c

c = -6

3) For the expression x² − 3x+ 1 = 0

Comparing with the general formula

ax² = x²

a = 1

Find b

-3x = bx

b = -3

Find c

c = 1

4) For the expression x² − 6x + 2x - 7 = 0

x² − 4x - 7 = 0

Comparing with the general formula

ax² = x²

a = 1

Find b

-4x = bx

b = -4

Find c

c = -7

4) For the expression − 2x = -3x² + 8

-3x² + 2x + 8 = 0

Comparing with the general formula

ax² = -3x²

a = -3

Find b

2x = bx

b = 2

Find c

c = 8

b) The general quadratic formula is expressed as:

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

1) To solve the quadratic expressions in (a), we only need to substitute the constants into the formula

$x=\frac{-(-4)\pm\sqrt{(-4)^2-4(1)(-5)} }{2(1)}\\x=\frac{4\pm\sqrt{(16+20} }{2(1)}\\x=\frac{4\pm\sqrt{36} }{2}\\x=\frac{4+6}{2} \ and \ \frac{4-6}{2} \\x=5 \ and \ -1$

2) 2x² + x− 6 = 0

$x=\frac{-1\pm\sqrt{(1)^2-4(2)(-6)} }{2(2)}\\x=\frac{-1\pm\sqrt{(1+48} }{4}\\x=\frac{-1\pm 7 }{2}\\x=\frac{-1+7}{2} \ and \ \frac{-1-7}{2} \\x=3 \ and \ -4$

3) x² − 3x + 1 = 0

$x=\frac{3\pm\sqrt{(-3)^2-4(1)(1)} }{2(1)}\\x=\frac{3\pm\sqrt{9-4} }{2}\\x=\frac{3\pm\sqrt{(9-4} }{2}\\x=\frac{3+ \sqrt{5} }{2} \ and \ x=\frac{3-\sqrt{5} }{2}$

4) For x² − 4x - 7 = 0

$x=\frac{4\pm\sqrt{(4)^2-4(1)(-7)} }{2(1)}\\x=\frac{4\pm\sqrt{16+28} }{2}\\x=\frac{4\pm\sqrt{44} }{2}\\x=\frac{4+ \sqrt{44} }{2} \ and \ x=\frac{4-\sqrt{44} }{2}$

5) For the expression -3x² + 2x + 8 = 0

$x=\frac{-2\pm\sqrt{(2)^2-4(-3)(8)} }{2(-3)}\\x=\frac{-2\pm\sqrt{4+96} }{-6}\\x=\frac{-2\pm\sqrt{100} }{-6}\\x=\frac{-2\pm 10} {-6}\\x=\frac{-2+10}{-6} \ and \ \frac{-2-10}{-6}\\x=\frac{-8}{6} \ and \ x = -2\\x = \frac{-4}{3} \ and \ x = -2$

Learn more here: brainly.com/question/1214333

3 0

2 years ago