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3 years ago

List all possible rational zeros of h(x) = x^3 - 5x^2 - 4x + 20. Then determine which, if any, are zeros.

Mathematics

1 answer:

devlian [24]3 years ago

4 0

Answer: x = {2, 5, -2}

Explanation:

see attachment

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Solve the equation. Round to the nearest hundredth. Show work.

Burka [1]

Answer:

$x=-0.75$

Step-by-step explanation:

The given equation is

$4^{-5x-7}=6^{2x-1}$

We take logarithm of both sides to base 10.

$\log(4^{-5x-7})=\log(6^{2x-1})$

$(-5x-7)\log(4)=(2x-1)\log(6)$

We expand the brackets to get;

$-5x\log(4)-7\log(4)=2x\log(6)-\log(6)$

Group similar terms;

$-7\log(4)+\log(6)=2x\log(6)+5x\log(4)$

$-7\log(4)+\log(6)=(2\log(6)+5\log(4))x$

$\frac{-7\log(4)+\log(6)}{(2\log(6)+5\log(4))}=x$

$x=-0.752478$

To the nearest hundredth.

$x=-0.75$

3 0

3 years ago

Simplify the radical expression below. <img src="https://tex.z-dn.net/?f=3%20%5Csqrt%7B7%7D%20-%20%5Csqrt%7B63%7D%20" id=

anzhelika [568]

So for this, we can simplify √63 as such:

$\sqrt{63}=\sqrt{7*9}=3\sqrt{7}$

Using the simplified version of √63, we can solve it:

$3\sqrt{7} -3\sqrt{7} =0$

Zero is your final answer.

4 0

4 years ago

Which choice shows the image of triangle QRS after the reflection over the x-axis followed by a rotation of 180° around the orig

Alex777 [14]

Answer:

Step-by-step explanation:

We see that triangle QRS is located in Quadrant III. (See attachment for labelling of quadrants)

Reflecting it over the x-axis means that we flip it over the x-axis, or we flip it vertically. Doing so, QRS will end up in Quadrant II.

Now, we need to rotate QRS 180 degrees about the origin. The quadrants are all 90 degrees away from each other, which means that if we rotate QRS about the origin 180 degrees, we'll end up two quadrants away from Quadrant II: we'll end in Quadrant IV.

Look at each of the answer choices. The only choice that features Q'R'S' (the image of QRS) in the fourth quadrant is the first choice, or A. So that's the answer.

~ an aesthetics lover