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posledela
3 years ago
11

A recipe calls for 3/4 cup of sugar for every 1/2 teaspoon of cinnamon. What is the unit rate in teaspoons of cinnamon per cup o

f sugar?
Mathematics
1 answer:
erma4kov [3.2K]3 years ago
7 0

Answer:

\frac{2}{3} teaspoons of cinnamon per cup of sugar.

Step-by-step explanation:

A recipe calls for \frac{3}{4} cups of sugar for every \frac{1}{2} teaspoons of cinnamon.

For one cup of sugar;

1 × \frac{1}{2} ÷ \frac{3}{4} = \frac{1}{2} × \frac{4}{3} = \frac{2}{3} teaspoons of cinnamon will be needed.

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The temperature was 78°F at 3 P.M. Each hour for
polet [3.4K]

Answer:

  66 °F

Step-by-step explanation:

At 4 P.M., the temperature had decreased by 3° from the temperature at 3 P.M., so was ...

  4 P.M. temp = 78 °F -3° = 75 °F

This was repeated until 7 P.M.

  5 P.M. temp = 75 °F -3° = 72 °F

  6 P.M. temp = 72 °F -3° = 69 °F

  7 P.M. temp = 69 °F -3° = 66 °F

The temperature at 7 P.M. was 66 °F.

__

Of course the repeated subtraction can be simplified using multiplication. The subtraction of 3° four times is equivalent to the subtraction of . . .

  (3°)(4) = 12°

That is, the temperature at 7 P.M. is ...

  78 °F -3°×4 = 78 °F -12° = 66 °F

6 0
2 years ago
Assume that population mean is to be estimated from the sample described. Use the sample results to approximate the margin of er
Vikentia [17]

Answer:

ME=1.998 \frac{4}{\sqrt{64}}=0.999 \approx 1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X =69 represent the sample mean for the sample  

\mu population mean

s=4.0 represent the sample standard deviation

n=64 represent the sample size  

Assuming the X follows a normal distribution

X \sim N(\mu, \sigma)

The sample mean \bar X have the following distribution:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

The margin of error for the sample mean is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

Since we have the sample standard deviation we can estimate the margin of error like this:

ME=t_{\alpha/2}\frac{s}{\sqrt{n}}

The next step would be find the value of \z_{\alpha/2}, \alpha=1-0.95=0.05 and \alpha/2=0.025

We can find the degrees of freedom like this:

df=n-1=64-1=63

And we can find the critical value with the following code in excel for example: "=T.INV(0.025,63)" and we got:

t_{\alpha/2}=\pm 1.998

And the margin of error would be :

ME=1.998 \frac{4}{\sqrt{64}}=0.999 \approx 1

3 0
3 years ago
Josh spent $42 on snacks.Maia spend $48 on hotdogs and hamburgers.Max spent 35 on rolls,condiments,lettuce,and tomatoes,and Mark
Andrei [34K]

Answer:

$165

Step-by-step explanation:

Money spent:

Josh=42

Maia=48

Max=35

Mark and Victoria = 40

35 + 40 + 42 + 48 = $165

3 0
3 years ago
Read 2 more answers
In AHIJ, the measure of ZJ=90°, IJ = 5 feet, and JH = 3.2 feet. Find the measure of
Dominik [7]

Answer:

32.6

Step-by-step explanation:

opp/adj = 3.2/5

I= tan -1(3.2/5)

I =32.6192

=32.6

3 0
3 years ago
PLSSSSSS HELP GIVING 10 POINTS
TEA [102]

Answer:

I'm pretty sure that it's C.

6 0
3 years ago
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