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Nat2105 [25]
3 years ago
8

PLSSSSSS HELP GIVING 10 POINTS

Mathematics
1 answer:
TEA [102]3 years ago
6 0

Answer:

I'm pretty sure that it's C.

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Prove 2^n > n for all n equal to or greater than 1. I mostly need help with how to solve the problem when it is greater than
noname [10]
If n is an integer, you can use induction. First show the inequality holds for n=1. You have 2^1=2>1, which is true.

Now assume this holds in general for n=k, i.e. that 2^k>k. We want to prove the statement then must hold for n=k+1.

Because 2^k>k, you have

2^{k+1}=2\times2^k>2k

and this must be greater than k+1 for the statement to be true, so we require

2k>k+1

for k>1. Well this is obviously true, because solving the inequality gives 3k>1\implies k>\dfrac13. So you're done.

If you n is any real number, you can use derivatives to show that 2^n increases monotonically and faster than n.
7 0
3 years ago
Show all work to multiply (3+ /(-16))(6-/(-64))
Reil [10]

Answer:

=50

Step-by-step explanation:

6 0
3 years ago
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Slove this for me please​
Alborosie

Answer:

-10

Step-by-step explanation:

divide both sides by -4

simplify to v+8=-2

subtract 8 from both sides

v=-10

6 0
3 years ago
The sum of seven angles of an octagon is 132 degrees each. Find the measure of the eighth angle.
Sauron [17]

the sum of the angles in an ngon (a polygon with n sides) is (n-2)*180

so an octagon has 8 sides and has a sum total of (8-2)*180=1080 degrees

if each of 7 angles is 132, then 1080=?+7*132

1080=?+924

156=?

the 8th angle is 156 degrees

6 0
3 years ago
Which of the following is characteristic of an epic hero?
jenyasd209 [6]
An epic hero must be most couragous than an actual oerson because that is what makes them brave and it gives them the ablitiy to fight
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3 years ago
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