![\bf \sqrt{n}< \sqrt{2n+5}\implies \stackrel{\textit{squaring both sides}}{n< 2n+5}\implies 0\leqslant 2n - n + 5 \\\\\\ 0 < n+5\implies \boxed{-5 < n} \\\\\\ \stackrel{-5\leqslant n < 2}{\boxed{-5}\rule[0.35em]{10em}{0.25pt}0\rule[0.35em]{3em}{0.25pt}2}](https://tex.z-dn.net/?f=%5Cbf%20%5Csqrt%7Bn%7D%3C%20%5Csqrt%7B2n%2B5%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bsquaring%20both%20sides%7D%7D%7Bn%3C%202n%2B5%7D%5Cimplies%200%5Cleqslant%202n%20-%20n%20%2B%205%20%5C%5C%5C%5C%5C%5C%200%20%3C%20n%2B5%5Cimplies%20%5Cboxed%7B-5%20%3C%20n%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B-5%5Cleqslant%20n%20%3C%202%7D%7B%5Cboxed%7B-5%7D%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D0%5Crule%5B0.35em%5D%7B3em%7D%7B0.25pt%7D2%7D)
namely, -5, -4, -3, -2, -1, 0, 1. Excluding "2" because n < 2.
First to get the equation you knew to understand one thing about perpendicular lines. The slope of the line is the opposite reciprocal of the perpendicular lines or the new slope is m = 10.
Then you use the formula
y = mx + b
you plug in your values from the point and the new slope.
(1,5) with new slope m
5= 10(1)+b
5-10=b
-5 = b
then make your new equation
y = 10x -5
that's your line that goes through point (1,5) and is perpendicular to the line given
Since we know what time Dennis' sister finished babysitting, we can calculate how much money she's made since 9p.m. Between 9 and 11 is 2 hours, so we know she made $16 ($8 per hour x 2 hours).
That means she made $22 before 9p.m. ($32 total - $16 made past 9p.m.)
So, you just need to figure out how many hours $22 is worth and subtract that number of hours from 9p.m. That will get you to the starting point of babysitting.
$22 / $5.50 = 4 so we know that $22 is 4 hours' worth of babysitting.
9p.m. - 4 hours is 5p.m., so we know that Dennis' sister started babysitting at 5p.m.
Hope this helps! If you liked this answer please rate it as brainliest!! Thank you!!!
Answer:
Step-by-step explanation:
First find the price of 1 ball by dividing 14.69/3. You get $4.90 rounded. Then multiply 4.89x100. It equals $49,000
