Find the 3rd term of an arithmetic sequence with t2= 9/2 and t5= 6
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Answer:
(-6, -5)
Step-by-step explanation:
Reflection across the y-axis leaves the point on the same horizontal line, but with the sign of its x-coordinate changed.
(x, y) ⇒ (-x, y) . . . . . reflection across the y-axis
(6, -5) ⇒ (-6, -5)
The image point is (-6, -5).
If the negative square root is found to be one of your solutions, then that is indicative of a pair of imaginary roots (the imaginary i). According to the conjugate rule, if you have one solution that is imaginary, you will have another but with the opposite sign. For example, if a solution to a quadratic is found to be 2 - i, then its conjugate, 2 + i is also a solution. They will ALWAYS go in pairs. Same thing with radical solutions. If one solution is found to be
then will also be a solution.