Answer:
Step-by-step explanation:
Given
--- [R, Y, C and B]
Required
Since each of the 4 balls are equally likely, their probability is:
From , we have:
So, the total arrangement of the 8 balls is:
The individual probability of each ball, when put together is
Lastly:
I already answered this question, if you look back in your questions you should find this answered along with another one. I'll do it again just in case you don't find it.
Answer:
{y,x} = {-4,-2}
Expanation:
Solve by Substitution :
// Solve equation [1] for the variable y
[1] y = 2x
// Plug this in for variable y in equation [2]
[2] -2•(2x) - 8x = 24
[2] - 12x = 24
// Solve equation [2] for the variable x
[2] 12x = - 24
[2] x = - 2
// By now we know this much :
y = 2x
x = -2
// Use the x value to solve for y
y = 2(-2) = -4
This can be solve by using the average cans of each student
collected and muliply it by the total students. Since for ms. Lee has 24
students and each student collected 18 cans on average, so the total can her
class collected on average is 432 cans. For mr galveshas 21 students and
collected 25 can per syudents on average, so the total is 525 cans. So 525 –
432 = 93 more cans the class of mr galvez collected
Answer:
I think they're both always but I'm not sure
If you're asking for extrema, like the previous posting
well
like the previous posting, since this rational is identical, just that the denominator is negative, the denominator yields no critical points
and the numerator, yields no critical points either, so the only check you can do is for the endpoints, of 0 and 4
f(0) = 0 <---- only maximum, and thus absolute maximum
f(4) ≈ - 0.19 <---- only minimum, and thus absolute minimum
