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4 years ago

The fraction 6/11 = the fraction 18/

2 answers:

kramer4 years ago

3 0

The fraction 6/11 is equivalent to the fraction of 18/33. They both have the same value. Simply multiply both the numerator and denominator by 3 to the fraction of 6/11 to get the new equivalent one.

Pavlova-9 [17]4 years ago

3 0

33 is the denominator. You can find this with the like terms. Putting 6/11 and 18/? Side by side, yo can see that 6 and 18 have a GCF of 6. You can use this to establish that 6 x 3 is 18. If you do something to the numerator, you just do it to the denominator to make it equal. So, with 6x 3, 11x 3 happens as well. So 6/11 is equal to 18/33

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3(5+2)-8+2(3), can someone help and also write it STEP BY STEP please this is Algebra 1

Nutka1998 [239]

Answer:3

Step-by-step explanation:3 (5+2) -8+2 (3)

distribute what’s inside parenthesis

3 (7) -8+2 (3)

now distribute any basic math outside the parenthesis

3 (7) -6 (3)

now multiply outside numbers to the inside numbers

3(7) -6(3)

21 -18 = 3

3 0

4 years ago

Read 2 more answers

A 3x3 magic square contains each of the numbers 1-9 arranged in such a way that each row, column and diagonal add up to the same

BaLLatris [955]

3×3 magic square (square matrix) of each row, column and diagonal in part (a) add up to 15. part add up to 165 which is 11 times part (a) and part (c)add up to 0 which is 0 times part (a). we deduce this by using trial and error approach.

Part (a) solving it through trial & error method we get the 3×3 magic square (square matrix)

4 9 2

3 5 7

8 1 6

In part (a) the total of each row, column, and diagonal is 15

again taking the same approach of trial and error we get

(b)

54 59.2 52

53 55 57

58 51 56

In part (b) the total of each row, column, and diagonal is 165 which is 11 times more than the total of each row, column, and diagonal in part (a). it is because at the center of part (a) magic square ( square matrix), the number is 5 and at the center of part (b) magic square, the number is 55 which is 11 times that of part (a) magic square( square matrix). we know that the number at the center of a magic square( square matrix) is responsible to make it a magic square ( square matrix) as other numbers are placed according to the number at the center to provide balance.

(c)

-1 4.2 -3

-2 0 2

3 -4 1

In part (c) the total of each row, column, and diagonal is 0. because the digit at the center is zero. In part (c) the total of each row, column, and diagonal is 0 which is 0 times more than the total of each row, column, and diagonal in part (a). it is because at the center of part (a) magic square( square matrix) , the number is 5 and at the center of part (b) magic square( square matrix) , the number is 0 which is 0 times that of the part (a) magic square ( square matrix) when compared. we know that the number at the center of a magic square ( square matrix) is responsible to make it a magic square (square matrix) as other numbers are placed according to the number at the center to provide balance.

learn more about magic square and matrix here

brainly.com/question/16834893

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4 0

2 years ago

Trivia took some fishbowls to a flea market. In the first hour she sold one-third of them and a third more; in the second hour,

a_sh-v [17]

<span>Number of bowls left after 1 hour = x - x/3 - 1/3 = 2x/3 - 1/3

</span><span> Number of bowls left after 2 hours = (2x/3 - 1/3) - (2x/3 - 1/3)/2 - 1/2 = 2x/6 - 1/6 - 1/2 = 2x/6 - 4/6 = x/3 - 2/3

keep doing this untill u reach 0 bowls left
and then u'll get ur answer
</span>

8 0

3 years ago

CAR WASH To raise money for their rowing club, Halima, Aisha, and Fatima

Dmitry [639]

Answer:

The area of the neighborhood in which they are advertising is 8.75 km²

Step-by-step explanation:

The coordinates of the street corners are;

(3, 15), (6, 4) and (11,9)

Therefore;

The distance between each street corner are found using the following formula;

$Distance, \ d=\sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

Substituting, using an online tool, we find the distances;

Between (3, 15) and (6, 4), d = √32.5 km

Between (6, 4) and (11,9), d = √12.5 km

Between (3, 15) and (11,9), d = 5 km

The area is given by Heron's formula as follows;

$A = \sqrt{s\cdot \left (s-a \right )\cdot \left (s-b \right ) \cdot \left ( s-c \right )}$

Where;

s = (√32.5 + √12.5 + 5)/2

a = √32.5

b = √12.5

c = 5

Substituting (using an online tool) the values gives;

A = 8.75 km²

The area of the neighborhood in which they are advertising is 8.75 km²

4 0

3 years ago

Three times a number increased by 4 is at least 16.what is the number

Galina-37 [17]

3x +4 >17
3x > 13
13/3
x is at least 4

3 0

3 years ago

Read 2 more answers