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Ronch [10]
3 years ago
15

what is an equation of the line that s perpendicullar to y-3=-4(x+2) and passes through the point (-5,7)

Mathematics
1 answer:
Sidana [21]3 years ago
7 0

Answer:

4y=x+33

y=x/4+33/4 (slope-intercept form)

Step-by-step explanation:

y-3 = -4(x+2)

y-3 -4x-8

y= -4x-8+3

y= -4x-5

m1 = -4

For perpendicularity

m2= -1/-4 = 1/4

The equation is

y-y1 = m2(x-x1)

y-7 = 1/4(x-(-5))

y-7 = x/4+5/4

Multiply through by 4

4y-28=x+5

4y=x+5+28

4y=x+33

Divide through by 4

y=x/4+33/4 (slope-intercept form)

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Answer:

k = 3

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Expanding the first term, we find 1/x at 8*1⁷(-2/x)¹ = -16/x

Then

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2 years ago
How Do You Write The Expression For Triple 9 Then Multiply 8
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3 years ago
R/3 = 7
dangina [55]
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3 years ago
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Rory's battery was full at 6:00 a.M, or t = 0. Which times could Rory's phone have been plugged into the charger? Select three o
Taya2010 [7]

Complete question:

Rory records the percentage of battery life remaining on his phone throughout a day. The graph represents the percentage of battery life remaining after a certain number of hours.

Rory’s battery was full at 6:00 a.m, or t = 0. Which times could Rory's phone have been plugged into the charger? Select three options.

12:00 p.m.

3:00 p.m.

5:00 p.m.

8:00 p.m.

11:00 p.m.

The graph is attached

Answer:

3:00 p.m

5:00 p.m

11:00 p.m

Step-by-step explanation:

From the graph, there are rise times, fall times and there are times the movement is steady (no rise or fall).

The rise time represents the time the phone was plugged. The fall time represents when the charger has been unplugged so the battery level starts depreciating. When it is constant, it means the battery level is at 100 but the charger is still connected to the phone.

We are told at initial condition, time was 6 a.m (t = 0). To get the exact time, we are to add the initial condition, i.e 6

From the graph, the times the phone could have been plugged are 8:00 to 12:00 hrs and 16:00 to 20:00 hrs.

Converting from 24 hr to 12 hr time, we have:

6 + 8hrs = 14:00 = 2:00 p.m

6 + 9hrs = 15:00 = 3:00 p.m

6 + 10 hrs = 16:00 = 4:00 p.m

6 + 11 hrs = 17:00 = 5:00 p.m

6 + 12 hrs = 18:00 = 6:00 p.m

6 + 16 hrs = 22:00 = 10:00 p.m

6 + 17 hrs = 23:00 = 11:00 p.m

6 + 18 hrs = 00:00 = 12:00 am

6 + 19 = 1 : 00 = 1:00 a.m

6 + 20 = 2:00 = 2:00 a.m

From the options given in the question, we have:

3:00 p.m; 5:00 p.m; 11:00 p.m

Therefore, times could Rory's phone have been plugged into the charger are:

3:00 p.m

5:00 p.m

11:00 p.m

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3 years ago
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miss Akunina [59]

Answer:

\large\boxed{\sf n^{th} \ term =3n}}

Step-by-step explanation:

Find common difference from subtracting any term in the sequence with the previous term.

\large{\sf 6-3}=3

Apply nth term formula.

\large{\sf a_n=a_1+(n-1)d

\large{\sf d=3 \ \ a_1=3}

\large{\sf a_n=3+(n-1)3

\large{\sf a_n=3+3n-3

\large{\sf a_n=3n}

3 0
3 years ago
Read 2 more answers
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