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tino4ka555 [31]
3 years ago
14

G/e^2-r=m-y please solve for e

Mathematics
1 answer:
allochka39001 [22]3 years ago
7 0
Move r to the right side of the equation, G/e^2=m-y+r. Multiply both sides by e^2, G=(m-y+r)*e^2. Then divide both sides by m-y+r (it cannot be 0), G/(m-y+r)=e^2. Then e=+-\sqrt(G/(m-y+r)).
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I’m so confused pls help...
Mazyrski [523]

Answer:

D) 24

<u>Steps:</u>

(2/10)=3/(x-9)

》1/5=3/(x-9)

》(x-9)=15

》x = 15+9

》x = 24

7 0
3 years ago
Find the area of square Park with the side of 15 1/5
Bezzdna [24]

Answer:

Square

Solve for area

A=225

a Side  

15

Step-by-step explanation:

7 0
3 years ago
Determine whether this pair of lines is parellel, perpendicular, or neither 6+2x=3y 3x+2y=9 Choose the correct answer below. A.
andriy [413]

Answer:

Option A. These two lines are perpendicular

Step-by-step explanation:

we know that

If two lines are parallel, then their slopes are equal

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

step 1

Convert the given equation A in slope intercept form

y=mx+b

where

m is the slope

b is the y-intercept

we have

6+2x=3y ----> equation A

Solve for y

That means----> isolate the variable y

Divide by 3 both sides

y=\frac{2}{3}x+2

so

m_A=\frac{2}{3}

step 2

Convert the given equation B in slope intercept form

y=mx+b

where

m is the slope

b is the y-intercept

we have

3x+2y=9 ----> equation B

Solve for y

That means----> isolate the variable y

subtract 3x both sides

2y=-3x+9

Divide by 2 both sides

y=-\frac{3}{2}x+4.6

so

m_B=-\frac{3}{2}

step 3

Compare the slopes

m_A=\frac{2}{3}

m_B=-\frac{3}{2}

The slopes are opposite reciprocal (the product is equal to -1)

therefore

These two lines are perpendicular

3 0
4 years ago
Simplify:<br> (7 + 2i)(9 - 6I)
Margarita [4]

Answer:

27

Step-by-step explanation:

hope this helped <3

4 0
4 years ago
What is the lcm for 32 40 16
vekshin1
<h3>Hey there! </h3><h3>Finding the LCM ((( LOWEST COMMON MULTIPLE) </h3><h2> 32:  32, 64, 96, 128, 160 </h2><h2>40:  40, 80,120, 160 </h2><h2>16: 16,32,48, 64,80,96, 112, (much more to come so we are going to skip them), and 160 </h2><h2>Your answer/ LCM is: 160 </h2><h2>Good luck on your assignment and enjoy your day! </h2><h2>LoveYourselfFirst:)</h2>
3 0
4 years ago
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