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docker41 [41]
3 years ago
7

The greater of two consecutive even integers is six less than twice the smaller. What are the integers?

Mathematics
2 answers:
AveGali [126]3 years ago
7 0

Let the integers be x and x+2. then:-

x + 2 = 2x - 6

x = 8

The integers are  8 and 10  Answer

goldenfox [79]3 years ago
3 0

Two consecutive integers can be written as x and x+1.

So, six less than twice the smaller is 2x-6, and this equals the greater, which is x+1. So the equality is

2x - 6 = x+1

Subtract x from both sides:

x-6 = 1

Add 6 to both sides:

x = 7

So, the integers are 7 and 8. In fact, the greater (8) is six less than twice the smaller (2*7-6 = 14-6=8)

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CALCULUS: For the function whose values are given in the table below, the integral from 0 to 6 of f(x)dx is approximated by a Re
ladessa [460]

The table gives values of <em>f(x)</em> at various <em>x</em> in the interval [0, 6], and you have to use them to approximate the definite integral,

∫₀⁶ <em>f(x)</em> d<em>x</em>

with a left-endpoint sum using 3 intervals of width 2. This means you have to

• split up [0, 6] into 3 subintervals of equal length, namely [0, 2], [2, 4], and [4, 6]

• take the left endpoints of these intervals and the values of <em>f(x)</em> these endpoints, so <em>x</em> ∈ {0, 2, 4} and <em>f(x)</em> ∈ {0, 0.48, 0.84}

• approximate the area under <em>f(x)</em> on [0, 6] with the sum of the areas of rectangles with dimensions 2 × <em>f(x)</em> (that is, width = 2 and height = <em>f(x)</em> for each rectangle)

So the Riemann sum is

∫₀⁶ <em>f(x)</em> d<em>x </em>≈ 2 ∑ <em>f(x)</em>

for <em>x</em> ∈ {0, 2, 4}, which is about

∫₀⁶ <em>f(x)</em> d<em>x </em>≈ 2 (0 + 0.48 + 0.84) = 2.64

making the answer A.

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