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juin [17]
3 years ago
13

Frank has a chance of receiving an A grade in statistics, a chance of receiving an A grade in geology, and a chance of receiving

A grades in both statistics and geology. Find the probability that he receives an A in statistics or geology (or both). Write your answer as a decimal (not as a percentage).
Mathematics
1 answer:
valentinak56 [21]3 years ago
8 0

Complete Question:

Frank has a 41% chance of receiving an A grade in statistics, a 36% chance of receiving an A grade in geology, and a 23% chance of receiving A grades in both statistics and geology. Find the probability that he receives an A in statistics or geology (or both) Write your answer as a decimal (not as a percentage).

Answer:

The probability that he receives an A in statistics or geology (or both) is:

0.54

Step-by-step explanation:

Probability of receiving an A grade in statistics = 41% or 0.41

Probability of receiving an A grade in geology = 36% or 0.36

Probability of receiving A grades in both statistics and geology = 23% or 0.23

Let S = statistics and p(S) = probability of A grade in statistics

Let G = geology and p(G) = probability of A grade in geology

Let p(S and G) = probability of A grades in statistics and geology.

The probability that he receives an A in statistics or geology (or both) is:

= p(S + G) - p(S and G)

= (0.41 + 0.36) - 0.23

= 0.54

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Evgen [1.6K]

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Answer:

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Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

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\bar X represent the sample mean

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s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

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