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3 years ago

Question 10 (3 points)

Mathematics

1 answer:

Zinaida [17]3 years ago

4 0

Answer:

$3,090.64

Step-by-step explanation:

We shall allocate a random letter to each value, with that I explain the formula.

Initial value of investment = $5,003.86 = P

Rate of interest = 3.7% = R

Compounding interval in a year = 365 = I

Total period = 13 years = T

Value of investment in compound interest formula shall be:

$= P \times (1 + \frac{R}{(I})^{(I \times T)}$

Now, putting values in the above equation:

$= 5,003.86 \times (1 + \frac{0.037}{365}) ^{(365\times13)}$

= $8,094.50

Thus, interest earned = Total value of investment on maturity - Initially invested amount

= $8,094.50 - $5,003.86 = $3,090.64

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If b2 + 2b − 24 = 0, and b < 0, what is the value of b?

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Step-by-step explanation:

Convert into factored form :

(b+6)(b-4)

Then make one of the terms 0.

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3 years ago

A second grade student is 4 feet tall. Her teacher is 5 2/3 feet tall. How many times as tall as the student is the teacher

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Answer:

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Step-by-step explanation:

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3 years ago

The 4th term of an arithmetic sequence is 12 and the 8th term is 36. Find the 17th term of the sequence.

Blizzard [7]

Answer: 90

Step-by-step explanation:

The formula for calculating the nth term of a sequence is given as :

$t_{n}$ = a + ( n - d )

Where a is the first term

d is the common difference and

n is the number of terms

This means that the 4th term of an arithmetic sequence will have the formula :

$t_{4}$ = a + 3d

And the 4th term has been given to be , 12 ,substituting into the formula we have

12 = a + 3d .............................. equation 1

Also substituting for the 8th term , we have

36 = a + 7d .............................. equation 2

Combining the two equations , we have

a + 3d = 12 ................... equation 1

a + 7d = 36 ------------ equation 2

Solving the system of linear equation by substitution method , make a the subject of formula from equation 1 , that is

a = 12 - 3d ................... equation 3

substitute a = 12 - 3d into equation 2 , equation 2 then becomes

12 - 3d + 7d = 36

12 + 4d = 36

subtract 12 from both sides

4d = 36 - 12

4d = 24

divide through by 4

d = 6

substitute d = 6 into equation 3 to find the value of a, we have

a = 12 - 3d

a = 12 - 3 ( 6)

a = 12 - 18

a = -6

Therefore , the 17th term of the sequence will be :

$t_{17}$ = a + 16d

$t_{17}$ = -6 + 16 (6)

$t_{17}$ = -6 + 96

$t_{17}$ = 90

Therefore : the 17th term of the sequence is 90

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4 years ago

Lincoln Middle School has a student body of 5 ^5 students. Each class has approximately 5 ^2 students. How many classes does the

Tamiku [17]

There are 5^5 students on the school and 5^2 students per class.

So, think:

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x classes ---------- 5^5 students

Multiply:

1 . 5^5 = x . 5^2

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5^5 = x.5^2

x = $\frac{5^5}{5^2}$

x = $5^{5-2}$

x = $5^3$

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4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%7Bx%7D%20" id="TexFormula1" title="f(x) = \sqrt{x} " alt="f(x) =

Georgia [21]

Answer: $\dfrac{1}{2\sqrt x}$

<u>Step-by-step explanation:</u>

$\lim_{h \to 0} f(x)=\dfrac{f(x+h)-f(x)}{h}$

f(x) = $\sqrt x\\$

f(x+h) = $\sqrt{x+h}$

$\lim_{h \to 0} f(x)=\dfrac{\sqrt{x+h}-\sqrt x}{h}$

$=\dfrac{\sqrt{x+h}-\sqrt x}{h}\bigg(\dfrac{\sqrt{x+h}+\sqrt x}{\sqrt{x+h}+\sqrt x}\bigg)$

$=\dfrac{(x + h)-(x)}{h(\sqrt{x+h}+\sqrt x)}$

$=\dfrac{h}{h(\sqrt{x+h}+\sqrt x)}$

$=\dfrac{1}{\sqrt{x+h}+\sqrt x}$

$=\dfrac{1}{\sqrt{x+0}+\sqrt x}$

$=\dfrac{1}{2\sqrt x}$

4 0

4 years ago