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Julli [10]
3 years ago
14

What is the equation in point slope form of the line that passes through the point

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
3 0

Answer:

\large\boxed{y+2=3(x-1)}

Step-by-step explanation:

\text{The point-slope form:}\\\\y-y_1=m(x-x_1)\\\\m-slope\\(x_1,\ y_1)-point\\\\\text{We have the slope}\ m=3\ \text{and the point (1, -2). Substitute:}\\\\y-(-2)=3(x-1)\\\\y+2=3(x-1)

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Answer:

The time interval when V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

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Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

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So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

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The schematic free body graphical representation of the above illustration was attached in the file below and the point when V_Q(t) \geq 60  is at 4 is obtained in the parabolic curve.

So, V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

Taking the integral of the time interval in order to determine the distance; we have:

distance = \int\limits^{3.519}_{1.866} {V_Q(t)} \, dt

= \int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt

= By using the Scientific calculator notation;

distance = 106.109 m

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