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Nimfa-mama [501]
3 years ago
11

lINE AB is formed by A(-10, 3) and B(2, 7). If line l is the PERPENDICULAR BISECTOR of line AB, write the equation of line l in

slope-intercept form (y = mx + b) mid point of AB in (x,y)
Mathematics
1 answer:
ValentinkaMS [17]3 years ago
4 0

Answer:

knbbbvccfcccvvcfcccc

Step-by-step explanation:

hhjjklllllllll

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HELP PLEASE !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
USPshnik [31]

Answer:

65mph

Step-by-step explanation:

Add 100 and 30 together then divide by 2. You get 65 miles per hour.

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3 years ago
The equation for bryce's running rate is y=5x and for Laila it is y=8x. Who is running faster?
Nonamiya [84]

Answer:

8x

Step-by-step explanation:

5 0
3 years ago
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Write the verbal phrase as an algebraic expression/equation: a number m cubed
hram777 [196]
Ttps://www.palmbeachstate.edu/prepmathlw/Documents/translatingkeywords.pdf

Try seeing if this link works it should help

5 0
3 years ago
PEOPLE WHO ARE GOOD AT MATH CAN YOU PLEASE HELP ME!!!
OlgaM077 [116]

The cost of using 19 HCF of water is $32.49

Given in the question:

The monthly cost (in dollars) of the water use (in dollars) is a linear function of the amount of water used (in hundreds of cubic feet, HCF)

The cost for using 17 HCF of water is using $32.13

and, the cost of using 35 HCF is $61.83.

To find the cost of using 19 HCF of water.

Now, According to the question:

The cost for using 17 HCF of water is  $32.13

and, the cost of using 35 HCF is $61.83.

To find the slope:

(17, 32.13) and (35, 61.83)

Slope = (61.83 - 32.13)/ (35 - 17) = 1.65

We know that:

Formula of slope :

y = mx + b

32.13 = 1.65 x 17 + b

b = 1.14

The equation will be :

C(x) = 1.65x + 1.14

Now, To find the cost of using 19 HCF of water.

C(19) = 1.65 × 19  + 1.14

C(19) = $32.49

Hence,  the cost of using 19 HCF of water is $32.49.

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6 0
1 year ago
Help me pls math genius
Alecsey [184]

Answer:

x = -3

y = -1

Step-by-step explanation:

in the given question :-

=》x - 4y = 1

=》x = 4y + 1

now replacing the value of x as ( 4y + 1 ) in equation (2)

=》3x + 2y = -11

=》3 (4y + 1) + 2y = -11

=》12y + 3 + 2y = -11

=》14y = -11 - 3

=》y = -14 ÷ 14

=》y = -1

now, putting the value of y in equation (1)

=》x - 4y = 1

=》x - ( 4 × -1 ) = 1

=》x + 4 = 1

=》x = 1 - 4

=》x = -3

6 0
3 years ago
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