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Andreyy89
3 years ago
7

One tank is filling at at a rate of 3/4 gallon per 2/3 minutes. A second tank is filling at a rate of 5/8 gallon per 1/2 minutes

. Which tank is filling faster?
Mathematics
2 answers:
VMariaS [17]3 years ago
8 0
3/4 times 3/2 (reciprocal of the second fraction) is 9/8 gallons per minute.
5/8 times 2/1 (reciprocal of the second fraction) is 10/8 gallons per minute

The second tank is filling faster.
aleksklad [387]3 years ago
4 0

Answer:

Step-by-step explanation:

Given

First tank is filling at a rate of \frac{3}{4} gallon per \frac{2}{3} minute i.e. per 40 sec

In 1 sec it fills \frac{3}{4\times 40}=\frac{3}{160} gallon

For second tank

Filling at a rate of \frac{5}{8} per \frac{1}{2} minutes

i.e. per 30 sec

in 1 sec it fills \frac{5}{8\times 30}=\frac{5}{240}

\frac{5}{240}>{3}{160}

thus second tank is filling at a faster rate.

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Find the missing side lengths. Leave your answers as radicals in simplest form.
sattari [20]

Answer:

see explanation

Step-by-step explanation:

To find x use the sine ratio in the right triangle and the exact value

sin60° = \frac{\sqrt{3} }{2} , then

sin60° = \frac{opposite}{hypotenuse} = \frac{14\sqrt{3} }{x} = \frac{\sqrt{3} }{2} ( cross- multiply )

x \sqrt{3} = 28\sqrt{3} ( divide both sides by \sqrt{3} )

x = 28

-----------------------------------------------------------

To find y use the tangent ratio in the right triangle and the exact value

tan60° = \sqrt{3} , then

tan60° = \frac{opposite}{adjacent} = \frac{14\sqrt{3} }{y} = \sqrt{3} ( multiply both sides by y )

14\sqrt{3} = y \sqrt{3} ( divide both sides by \sqrt{3} )

y = 14

3 0
4 years ago
PLEASEEE HELP<br> Questions 4 and 5
Ilya [14]

Answer:

  • Given and explained below.

question 4

using sine rule:

\sf sinx = \frac{opp}{hyp}

\sf sinx = \frac{11}{13}

\sf x = sin^{-1}(\frac{11}{13} )

\sf x = 57.8

question 5

using cosine rule:

\sf cosx =\frac{adj}{hyp}

\sf cos(31) =\frac{x}{17}

\sf cos(31)*17 =x

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4 0
2 years ago
Read 2 more answers
Pls help asap the best I can do is 50 points
lutik1710 [3]

Step-by-step explanation:

8.a.

a function is something that looks like

y = ax + b or similar.

it describes the way to calculate the result for whatever input value you can come up with.

so,

C = 12×d + 8

you could also say

C(d) = 12×d + 8

as, when you rent, you have to pay these $8 in any case, no matter how long you stay, and you need to pay $12 per day you stay.

funny thing is : you understood this perfectly well when doing b.

c.

the constant rate of change is always the factor of the input variable. here : 12

it is the ratio of (y change) / (x change)

or here (C change / d change).

it indicates that for any increase of d by 1 (staying one day longer) the charges C increase by 12.

9.a.

remember, what we just said about the rate of change ?

it is (result change) / (input change).

between 2010 and 2015

the input changed by +5 (from 2010 to 2015).

the result changed by +6.25 (from 37 to 43.25).

the rate of change is therefore

6.25/5 = 1.25 = 1 1/4 = 5/4

the function is therefore

population in millions = (years since 2010)×5/4 + 37

p = y×5/4 + 37

b.

now we want to find the number of years (y) so that the result of that equation is 50.

50 = y×5/4 + 37

13 = y×5/4

52 = 5y

y = 52/5 = 10.4

so, this will be during the 11th year after 2010 = 2021.

10.

be careful and concentrate.

you see that the sequence goes up 20, when n goes up 5 (and not just 1) ? there was your initial mistake.

a.

again, remember the change rate : it is result change / input change.

so, we have here 20/5 = 4.

so,

C(n) = 4×n + 50

b.

n = 12

C(12) = 4×12 + 50 = 98

c.

now we have C(n), and want to find for which n this is true.

C(n) = 78

78 = 4×n + 50

28 = 4×n

n = 7

after 7 visits the costs are 78.

there are the basic costs of 50 (for n = 0 or 0 visits) and then extra 4 for every visit.

d.

the x-axis is for the number of visits, the y-axis for the costs.

so, the line starts at the point (0, 50), and then passes through the points of the original table (5, 70), (10, 90), (15, 110). and if you want you can calculate the points for higher x (or number of visits).

4 0
3 years ago
If a and b are rational numbers and 6/(3√2-2√3 ) = a √2-b √3 , then find the values of a and b.
eduard

Answer:

=3–√−13–√+1⋅3–√−13–√−1

=(3–√−1)23–√2−12

=3–√2+12−23–√3−1

=4−23–√2

2−13–√

a=2,b=−1.

Step-by-step explanation:

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3 years ago
rosa want to buy snacks at the snack stand. Snacks cost $2.50 each. write and solve an inequality to find the number of snacks r
Keith_Richards [23]

Answer:

18≤ 2.50x

because there is only so much money she is allowed to spend has to be less than or equal to 18

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3 years ago
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