Question

What is the area of the figure below ?

Answer 1

Answer:

58 in²

Step-by-step explanation:

Separate the figure into 3 separate shapes:

• The triangle at the bottom
• The triangle at the top
• The trapezoid in the middle

The find the formulas you will use to solve each one:

• Trapezoid: $[h(b1 + b2)]0.5$

• Triangles: $0.5 (b * h)$

Plug in the values:

• Triangle at the top: (8 x 6)0.5 = 24 in²

• Trapezoid in the middle: [5(6 + 4)]0.5 = 25 in²
• Triangle at the bottom: (8 x 6)0.5 = 9 in²

Then add up all of the values:

• 24 + 25 + 9 = 58

Add the term:

• 58 in²

Answer 2

Answer:

Step-by-step explanation:

Area of the figure = area of the down triangle + area of trapezium + area of the upper triangle

Down triangle:

Base b = 8 in

Height = 6 in

$Area = \frac{1}{2}bh\\=\frac{1}{2}*8*6\\\\=4*6$

= 24 in²

Trapezium:

bases a = 4 in & b = 6 in

Height h =  5 in

$Area=\frac{(a+b)h}{2}\\\\=\frac{(4+6)*5}{2}\\\\=\frac{10*5}{2}\\\\=5*5$

= 25 in²

Area of the upper triangle:

Base b = 6 in

Height = (8 - 5) = 3 in

$Area=\frac{1}{2}bh\\\\=\frac{1}{2}*6*3\\\\=3*3$

= 9 in²

Area of the figure = 24 + 25 + 9 = 58 in²